The problem asks for the length of side AC in a triangle \(\Delta ABC\), given the lengths of sides AB and BC, and the angle between them (\(\angle B = 90^\circ\)).
Since \(\angle B = 90^\circ\), the triangle \(\Delta ABC\) is a right-angled triangle. The side AC is opposite the right angle, making it the hypotenuse. Sides AB and BC are the legs of the triangle.
We can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides (legs).
The formula is: \(AC^2 = AB^2 + BC^2\)
We are given \(AB = 13\text{ cm}\) and \(BC = 84\text{ cm}\).
\(AC^2 = (13\text{ cm})^2 + (84\text{ cm})^2\)
\(13^2 = 169\)
\(84^2 = 7056\)
\(AC^2 = 169\text{ cm}^2 + 7056\text{ cm}^2\)
\(AC^2 = 7225\text{ cm}^2\)
\(AC = \sqrt{7225\text{ cm}^2}\)
\(AC = 85\text{ cm}\)
Therefore, the length of AC is 85 cm.
In the given figure, if \(RS = 3\sqrt{3} \text{ cm}\) and \(RPS\) is an equilateral triangle, then find the value of \(QR\)
For a pair of similar triangles shown in the figure, the angles made at $B$ and $R$ are same in both the triangles $BAC$ and $RAQ$. If the ratio of the areas of the two triangles is 2:1, and if the area of $BAC$ is $100\text{ cm}^2$ then what is the area of $RAQ$ in sq.cm.?

In a right angled triangle, with angle at A being , the side $AB$ is of length 4cm and $BC$ is 15 cm. What is the length of side $AC$?

What is the angle at $B$ in the triangle $ABC$, if the angle made at $K$ is $30^\circ$ and the triangles shown in the figure are similar?

What is \(AB + BC\) equal to?
In the given figure, if \(RS = 3\sqrt{3} \text{ cm}\) and \(RPS\) is an equilateral triangle, then find the value of \(QR\)
For a pair of similar triangles shown in the figure, the angles made at $B$ and $R$ are same in both the triangles $BAC$ and $RAQ$. If the ratio of the areas of the two triangles is 2:1, and if the area of $BAC$ is $100\text{ cm}^2$ then what is the area of $RAQ$ in sq.cm.?
