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Question

In a division problem, the divisor is 4 times the quotient and 2 times the remainder. If the remainder is 32, then find the dividend.

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

1056

Let the quotient be q, the divisor be d, and the remainder be r. According to the problem, we have the following relations:
d = 4q (the divisor is 4 times the quotient),
d = 2r (the divisor is 2 times the remainder),
r = 32 (remainder is 32).
From the equation d = 2r, we get d = 64. Now, substitute d = 64 into d = 4q to get 64 = 4q, so q = 16.
Now, using the division formula: Dividend = (Divisor × Quotient) + Remainder = 64 × 16 + 32 = 1024 + 32 = 1056.

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  1. If the 8-digit number 888x53y4 is divisible by 72, then what is the value of (7x + 2y), for the maximum value of y?

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    select the correct answer using the code given below:

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