If a perfect square, not divisible by 6, be divided by 6, the remainder will be
1, 3 or 4
Let the perfect square be n², where n is not divisible by 6. When n² is divided by 6, the remainder will be 1, 3, or 4. Example: 12² = 1 (remainder 1), 2² = 4 (remainder 4), 3² = 9 (remainder 3), 4² = 16 (remainder 4), 5² = 25 (remainder 1).
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Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.
Which of the following is/are correct?
1. S is always divisible by 74.
2. S is always divisible by 9.
select the correct answer using the code given below:
