Decoding the Code Language

This question involves solving a simple substitution cipher based on comparing given coded phrases.

Step 1: Analyze Sentence Codes

We are given three sentences and their corresponding codes:

• "The book is interesting" is coded as "mo no lo po"
• "The book is boring" is coded as "mo no to po"
• "The movie is interesting" is coded as "do no lo po"

Step 2: Identify Word-Code Correspondences

By comparing the sentences and codes, we can find the code for each word:

• Compare "The book is interesting" (mo no lo po) and "The book is boring" (mo no to po). The common part is "The book is" / "mo no po". The differing words are "interesting" and "boring", and the differing codes are "lo" and "to". This implies:
  • interesting = lo
  • boring = to
• Compare "The book is interesting" (mo no lo po) and "The movie is interesting" (do no lo po). The common part is "The ... is interesting" / "no lo po". The differing words are "book" and "movie", and the differing codes are "mo" and "do". This implies:
  • book = mo
  • movie = do
• The word "is" is present in all three sentences, and "no" is present in all three codes. Thus:
  • is = no
• The word "The" is present in all three sentences, and "po" is present in all three codes. Thus:
  • The = po

Step 3: Summarize Word Codes

The final mapping is:

Step 4: Determine Code for Target Phrase

We need the code for "The movie is boring". Using the mapping:

• The = po
• movie = do
• is = no
• boring = to

The set of codes is {do, no, po, to}.

Observing the order in the examples (e.g., "The movie is interesting" -> "do no lo po"), the code order appears to be: movie (do), is (no), The (po), interesting (lo). Applying this order to our target phrase "The movie is boring": movie (do), is (no), The (po), boring (to).

Therefore, the code is do no po to.