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Question

In a circle of radius 14 cm, APB is a shorter arc and P is the midpoint of the arc. Let C be the midpoint of the chord AB and PC = 7 cm. What is the length of the chord AP?

This question was previously asked in
CDS 2 2025 Maths Question Paper (14-Sep-2025)
The correct answer is
14 cm

Circle Geometry: Understanding the Problem

This problem involves finding the length of a chord within a circle using geometric properties. We are given the circle's radius, information about an arc and its midpoint, a chord related to that arc, the midpoint of the chord, and the distance between the arc's midpoint and the chord's midpoint.

Given Information Details

  • Radius of the circle: \(r = 14\) cm.
  • APB is a shorter arc.
  • P is the midpoint of the arc APB.
  • AB is the chord corresponding to the arc APB.
  • C is the midpoint of the chord AB.
  • The distance PC = 7 cm.
  • We need to find the length of the chord AP.

Step-by-Step Solution for Chord AP

Visualizing the Circle Geometry

Let O be the center of the circle. Since P is the midpoint of the arc APB, the line segment OP passes through the center and is perpendicular to the chord AB. Also, C is the midpoint of the chord AB, which means OC is perpendicular to AB. Therefore, O, C, and P are collinear points lying on the radius passing through P.

We have OA = OB = OP = 14 cm (radii of the circle).

Calculating Distance from Center (OC)

Since O, C, and P are collinear, the distance OC can be found using the lengths OP and PC.

We know that OP is the radius, so \(OP = 14\) cm.

We are given \(PC = 7\) cm.

The distance OC is the difference between OP and PC:

\(OC = OP - PC\)

\(OC = 14 \text{ cm} - 7 \text{ cm} = 7 \text{ cm}\)

So, the distance of the chord AB from the center O is 7 cm.

Finding Angle AOC using Trigonometry

Consider the right-angled triangle \(\triangle OCA\) (since OC is perpendicular to AB).

In \(\triangle OCA\), we have:

  • Hypotenuse \(OA = 14\) cm (radius).
  • Adjacent side \(OC = 7\) cm.

We can find the angle \(\angle AOC\) using the cosine function:

\(\cos(\angle AOC) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{OC}{OA}\)

\(\cos(\angle AOC) = \frac{7}{14} = \frac{1}{2}\)

The angle whose cosine is \(\frac{1}{2}\) is \(60^\circ\).

Therefore, \(\angle AOC = 60^\circ\).

Determining Angle AOP for Arc AP

Since P is the midpoint of the arc AB, the line OP bisects the angle \(\angle AOB\). This means \(\angle AOC = \angle BOC\).

The angle subtended by the chord AB at the center is \(\angle AOB = \angle AOC + \angle BOC\).

Since \(\angle AOC = 60^\circ\), then \(\angle BOC = 60^\circ\).

\(\angle AOB = 60^\circ + 60^\circ = 120^\circ\).

Now, consider the arc AP. Since P is the midpoint of arc AB, the arc AP is half of the arc AB. The angle subtended by arc AP at the center is \(\angle AOP\).

\(\angle AOP = \frac{1}{2} \angle AOB\)

\(\angle AOP = \frac{1}{2} (120^\circ) = 60^\circ\).

Calculating Chord AP Length

Now, let's focus on the triangle \(\triangle OAP\). We know the lengths of two sides and the angle between them:

  • \(OA = 14\) cm (radius).
  • \(OP = 14\) cm (radius).
  • \(\angle AOP = 60^\circ\).

Since two sides (OA and OP) are equal and the angle between them (\(\angle AOP\)) is \(60^\circ\), the triangle \(\triangle OAP\) is an equilateral triangle.

In an equilateral triangle, all sides are equal in length.

Therefore, the length of the chord AP is equal to the lengths of OA and OP.

\(AP = OA = OP = 14\) cm.

Final Result for Chord Length

The length of the chord AP is calculated to be 14 cm.

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