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Question

In a certain code language, PISTA is written as OGPPV. How will ALMOND be written as in that language?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
ZJJKIX

Analyzing the Coding Pattern

The question asks us to decipher the code where 'PISTA' is transformed into 'OGPPV' and apply this logic to encode 'ALMOND'. We first identify the relationship between the letters of the original word and the coded word.

We list the letters and their corresponding positions in the English alphabet (A=1, Z=26):

  • P (16) -> O (15)
  • I (9) -> G (7)
  • S (19) -> P (16)
  • T (20) -> P (16)
  • A (1) -> V (22)

Now, let's determine the shift for each position:

  • P (16) to O (15): The shift is $15 - 16 = -1$.
  • I (9) to G (7): The shift is $7 - 9 = -2$.
  • S (19) to P (16): The shift is $16 - 19 = -3$.
  • T (20) to P (16): The shift is $16 - 20 = -4$.
  • A (1) to V (22): Considering the alphabet wraps around (A follows Z backwards), the shift is calculated as: $22 - 1 = 21$? No. Let's check the reverse shift. A is 1. V is 22. Moving backward from A: A -> Z (-1), Z -> Y (-2), Y -> X (-3), X -> W (-4), W -> V (-5). So, the shift is -5. Using modular arithmetic: $(1 - 5) \mod 26 = -4 \mod 26 = 22$. This corresponds to V.

The established pattern is a sequential backward shift of -1, -2, -3, -4, -5 for the letters based on their position in the word.

Applying the Pattern to ALMOND

The word 'ALMOND' has 6 letters. We will apply the backward shifts -1, -2, -3, -4, -5, and -6 sequentially.

  • A (1st letter, position 1): Shift -1. Calculation: $(1 - 1) \mod 26 = 0 \mod 26$. This corresponds to the 26th letter, Z.
  • L (2nd letter, position 12): Shift -2. Calculation: $(12 - 2) \mod 26 = 10 \mod 26$. This corresponds to the 10th letter, J.
  • M (3rd letter, position 13): Shift -3. Calculation: $(13 - 3) \mod 26 = 10 \mod 26$. This corresponds to the 10th letter, J.
  • O (4th letter, position 15): Shift -4. Calculation: $(15 - 4) \mod 26 = 11 \mod 26$. This corresponds to the 11th letter, K.
  • N (5th letter, position 14): Shift -5. Calculation: $(14 - 5) \mod 26 = 9 \mod 26$. This corresponds to the 9th letter, I.
  • D (6th letter, position 4): Shift -6. Calculation: $(4 - 6) \mod 26 = -2 \mod 26$. This corresponds to the 24th letter, X (since $-2 + 26 = 24$).

Combining the resulting letters, we get the coded word: ZJJKIX.

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Important Questions from Coding Decoding

  1. Each vowel In the word “CAPSULE” Is changed to the previous letter In the English alphabetical series and each consonant is changed to the following letter in the English alphabetical series. In the newly formed word, how many alphabets are there in the English alphabetical series between the alphabet which is 3rd from the left and 3rd from the right?

  2. In a certain code language, if ‘PDFJARS’ is written as ‘OCELZQR’ and ‘MHCXBTU’ is written as ‘LGBZAST’, how will ‘ZVDGENQ’ be written in the same code language?

  3. Which of the following letter-clusters will replace the question mark (?) in the given series to make it logically complete?

    ADZ, GJF, MPL, SVR, ?

  4. In a certain code language, 'BENT' is coded as '3198' and 'DEBT' is coded as '8316'. What is the code for 'N' in the given code language?

  5. In a certain code language, GAME is written as TUZANOVW, and CAR is written as XYZAIJ. How will POST be written in that language ?

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