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Question

If A = 26 and T = 7, then AUTHENTIC = ?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
266719221371824

Decoding the AUTHENTIC Word Puzzle

This question involves a substitution cipher where letters map to numbers. We need to find the rule based on the given examples (A=26, T=7) and apply it to the word AUTHENTIC.

Identifying the Cipher Rule

We are given the following mappings:

  • A = 26
  • T = 7

The standard alphabetical positions are A=1 and T=20.

Since the first letter A (position 1) is assigned the value 26, this suggests a reverse alphabetical order mapping (Z=1, Y=2, ..., B=25, A=26). We can verify this rule using the second given mapping, T=7.

The standard position of T is 20. The reverse position is calculated using the formula: Reversed Position = $27 - \text{Standard Position}$.

For T, the calculation is: $27 - 20 = 7$. This matches the given value T = 7.

Thus, the cipher rule used is the reversed alphabetical position for each letter.

Applying the Rule to AUTHENTIC

Now, we apply this rule to find the numerical code for each letter in the word AUTHENTIC:

Letter Standard Position Reversed Position Numerical Code
A 1 $27 - 1 = 26$ 26
U 21 $27 - 21 = 6$ 6
T 20 $27 - 20 = 7$ 7
H 8 $27 - 8 = 19$ 19
E 5 $27 - 5 = 22$ 22
N 14 $27 - 14 = 13$ 13
T 20 $27 - 20 = 7$ 7
I 9 $27 - 9 = 18$ 18
C 3 $27 - 3 = 24$ 24

Constructing the Final Code

Concatenate the numerical codes for each letter in the order they appear in AUTHENTIC:

26, 6, 7, 19, 22, 13, 7, 18, 24

The resulting numerical code for AUTHENTIC is 266719221371824.

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