The question involves a mixture with a given total volume and a specific ratio between its components (juice and water). The ratio of juice to water is given as $3:2$. This means that for every 3 parts of juice, there are 2 parts of water in the mixture.
To find the total number of parts in the ratio, we add the individual parts:
Total parts = (Parts of Juice) + (Parts of Water) = $3 + 2 = 5$ parts.
The total volume of the mixture is given as 20 Liters (L).
We know that these 5 total parts make up the entire 20 L mixture. We can determine the volume represented by one part:
Volume of one part = $\frac{\text{Total Volume}}{\text{Total Parts}} = \frac{20 \text{ L}}{5 \text{ parts}} = 4 \text{ L/part}$.
Now, we can calculate the specific amount of juice in the mixture. Since the ratio indicates 3 parts of juice:
Amount of Juice = (Parts of Juice) $\times$ (Volume of one part)
Amount of Juice = $3 \text{ parts} \times 4 \text{ L/part} = 12 \text{ L}$.
Similarly, we can find the amount of water:
Amount of Water = (Parts of Water) $\times$ (Volume of one part)
Amount of Water = $2 \text{ parts} \times 4 \text{ L/part} = 8 \text{ L}$.
To verify, the total volume is $12 \text{ L} + 8 \text{ L} = 20 \text{ L}$, which matches the given total volume.
Based on the calculation, the amount of juice in the 20 L mixture is 12 L.
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A vessel full of water weighs 4o kg. If it is one-third filled, its weight becomes 20 kg. What is the weight of the empty vessel?
Two equal glasses of same type are respectively 1/3 and 1/4 full of milk. They are then filled up with water and the contents are mixed in a pot. What is the ratio of milk and water in the pot?