If x = X- \(\bar{X}\) and y = Y - \(\bar{Y}\) and the number of pairs (X, Y) is n, then the Karl Pearson's coefficient of correlation is:
Karl Pearson's correlation in terms of original values is
\[r=\dfrac{\sum (X-\bar{X})(Y-\bar{Y})}{\sqrt{\sum (X-\bar{X})^2\,\sum (Y-\bar{Y})^2}}\]
Substituting \(x=X-\bar{X}\) and \(y=Y-\bar{Y}\) gives
\[r=\dfrac{\sum xy}{\sqrt{\sum x^2\,\sum y^2}}\]
Note that \(n\) cancels because it appears in both numerator and denominator when expressed via covariances and standard deviations. Hence the correct expression is \(\dfrac{\sum xy}{\sqrt{\sum x^2\sum y^2}}\).
The product of partial regression coefficient \(b_1{_2}{_.3}\) \(b_2{_3}{_.1}\) \(b_3{_1}{_.2}\) equals to:
If six hand-writings were ranked by two judges in a competition and the rankings are as follows:
| Hand Writing | ||||||
| 1 | 2 | 3 | 4 | 5 | 6 | |
| Judge1 | 6 | 5 | 4 | 3 | 2 | 1 |
| Judge2 | 1 | 2 | 3 | 4 | 5 | 6 |
If the difference between the rank of the 4 observations are 2.5, 0.5, -1.5, -1.5, then Spearman's rank correlation coefficient equals to:
For the data set
| x: | 1 | 2 | 3 | 4 |
| y: | 4 | 5 | 3 | 2 |
the regression coefficient b yx (y on x) equals to:
For the two variables X and Y, the following observations are tabulated.
| X: | 3 | 4 | 4 |
| Y: | 10 | 10 | 9 |
The Spearman's correlation coefficient is:
For the variables X and Y, we collect 4 observations with ∑x = 10, ∑y = 14, ∑x 2= 30, ∑y 2= 54, ∑xy = 31. The regression line y on x is
The coefficient of correlations is r between X and Y having standard deviation σx and σy. The tangent of the between two lines of regression is:
In Spearman rank correlation coefficient r s= 1 - \(\dfrac{6∑ d^2}{n(n^2-1)}\) , the maximum value of ∑d 2in case of untied rank is:
If the correlation coefficient between x and y is 0.5 and the regression coefficient of y on x is 0.5, then the regression coefficient of x on y is:
If X 1, X 2, … X nis a simple random sample without replacement of size n from a finite population of N units with mean μ and variance σ 2, the covariance of (X i, Xj ) will be: