For the data set the regression coefficient b yx (y on x) equals to:x: 1 2 3 4 y: 4 5 3 2
-0.8
The question asks us to calculate the regression coefficient of y on x, denoted as \(b_{yx}\), for the given dataset. The regression coefficient \(b_{yx}\) represents the average change in the dependent variable y for a one-unit change in the independent variable x. It is a key component in linear regression, helping us understand the linear relationship between two variables.
The formula to calculate the regression coefficient \(b_{yx}\) for a set of n data points \((x_i, y_i)\) is:
\[b_{yx} = \frac{n \Sigma xy - (\Sigma x)(\Sigma y)}{n \Sigma x^2 - (\Sigma x)^2}\]
Where:
The given dataset is:
| x | y |
|---|---|
| 1 | 4 |
| 2 | 5 |
| 3 | 3 |
| 4 | 2 |
Let's calculate the required sums:
Now, substitute these values into the formula for \(b_{yx}\):
\[b_{yx} = \frac{(4)(31) - (10)(14)}{(4)(30) - (10)^2}\]
\[b_{yx} = \frac{124 - 140}{120 - 100}\]
\[b_{yx} = \frac{-16}{20}\]
\[b_{yx} = -0.8\]
The calculated regression coefficient \(b_{yx}\) is -0.8.
Comparing this value with the given options:
The calculated value of -0.8 matches Option 4.
| Concept | Description | Formula (for y on x) |
|---|---|---|
| Regression Coefficient \(b_{yx}\) | Measures the change in y per unit change in x. Represents the slope of the regression line. | \(b_{yx} = \frac{n \Sigma xy - (\Sigma x)(\Sigma y)}{n \Sigma x^2 - (\Sigma x)^2}\) |
| Regression Line (y on x) | The line that best fits the data points, representing the linear relationship \(y = a_{yx} + b_{yx}x\). | \(y - \bar{y} = b_{yx}(x - \bar{x})\) or \(y = \bar{y} - b_{yx}\bar{x} + b_{yx}x\) where \(a_{yx} = \bar{y} - b_{yx}\bar{x}\) |
| Regression Coefficient \(b_{xy}\) | Measures the change in x per unit change in y (regression of x on y). | \(b_{xy} = \frac{n \Sigma xy - (\Sigma x)(\Sigma y)}{n \Sigma y^2 - (\Sigma y)^2}\) |
Linear regression is a statistical method used to model the linear relationship between a dependent variable (in this case, y) and one or more independent variables (in this case, x). The equation of a simple linear regression line (y on x) is typically written as \(y = a + bx\), where:
The goal of linear regression is to find the values of \(a\) and \(b\) that result in the line that best fits the data. The "best fit" is usually defined using the method of least squares, which minimizes the sum of the squared differences between the observed y values and the y values predicted by the line.
The regression coefficient \(b_{yx}\) indicates both the strength and direction of the linear relationship between y and x. A negative value like -0.8 suggests a negative linear relationship: as x increases, y tends to decrease. The magnitude (0.8) indicates the strength of this relationship (larger absolute value means stronger relationship).
The product of partial regression coefficient \(b_1{_2}{_.3}\) \(b_2{_3}{_.1}\) \(b_3{_1}{_.2}\) equals to:
If six hand-writings were ranked by two judges in a competition and the rankings are as follows:
| Hand Writing | ||||||
| 1 | 2 | 3 | 4 | 5 | 6 | |
| Judge1 | 6 | 5 | 4 | 3 | 2 | 1 |
| Judge2 | 1 | 2 | 3 | 4 | 5 | 6 |
If the difference between the rank of the 4 observations are 2.5, 0.5, -1.5, -1.5, then Spearman's rank correlation coefficient equals to:
For the two variables X and Y, the following observations are tabulated.
| X: | 3 | 4 | 4 |
| Y: | 10 | 10 | 9 |
The Spearman's correlation coefficient is:
For the variables X and Y, we collect 4 observations with ∑x = 10, ∑y = 14, ∑x 2= 30, ∑y 2= 54, ∑xy = 31. The regression line y on x is
The coefficient of correlations is r between X and Y having standard deviation σx and σy. The tangent of the between two lines of regression is:
In Spearman rank correlation coefficient r s= 1 - \(\dfrac{6∑ d^2}{n(n^2-1)}\) , the maximum value of ∑d 2in case of untied rank is:
If the correlation coefficient between x and y is 0.5 and the regression coefficient of y on x is 0.5, then the regression coefficient of x on y is:
If X 1, X 2, … X nis a simple random sample without replacement of size n from a finite population of N units with mean μ and variance σ 2, the covariance of (X i, Xj ) will be:
If x = X- \(\bar{X}\) and y = Y - \(\bar{Y}\) and the number of pairs (X, Y) is n, then the Karl Pearson's coefficient of correlation is: