If \(\rm \sum x_i = 20, \sum x_i^2=200\) and n = 10 for an observed variable x, then what is the coefficient of variation?
200
The coefficient of variation (CV) is a statistical measure of the relative variability of data. It is the ratio of the standard deviation to the mean, often expressed as a percentage. It helps compare the degree of variation between data sets, even if their means are drastically different.
The formula for the coefficient of variation (CV) is:
\( \text{CV} = \frac{\sigma}{\bar{x}} \times 100\% \)
Where:
To find the coefficient of variation, we first need to calculate the mean (\( \bar{x} \)) and the standard deviation (\( \sigma \)) from the given data.
The mean is the average of the observations. The formula for the mean is:
\( \bar{x} = \frac{\sum x_i}{n} \)
Given:
Substitute the values into the formula:
\( \bar{x} = \frac{20}{10} \)
\( \bar{x} = 2 \)
So, the mean of the observed variable x is 2.
The standard deviation is the square root of the variance. The variance (\( \sigma^2 \)) can be calculated using the formula:
\( \sigma^2 = \frac{\sum x_i^2}{n} - (\bar{x})^2 \)
Given:
Substitute the values into the variance formula:
\( \sigma^2 = \frac{200}{10} - (2)^2 \)
\( \sigma^2 = 20 - 4 \)
\( \sigma^2 = 16 \)
Now, calculate the standard deviation (\( \sigma \)) by taking the square root of the variance:
\( \sigma = \sqrt{\sigma^2} = \sqrt{16} \)
\( \sigma = 4 \)
The standard deviation is 4.
Now that we have the standard deviation (\( \sigma = 4 \)) and the mean (\( \bar{x} = 2 \)), we can calculate the coefficient of variation:
\( \text{CV} = \frac{\sigma}{\bar{x}} \times 100 \)
\( \text{CV} = \frac{4}{2} \times 100 \)
\( \text{CV} = 2 \times 100 \)
\( \text{CV} = 200 \)
The coefficient of variation is 200. The options are given as numerical values without the percentage symbol, so the answer is 200.
| Statistic | Formula | Calculation | Result |
|---|---|---|---|
| Mean (\(\bar{x}\)) | \(\frac{\sum x_i}{n}\) | \(\frac{20}{10}\) | 2 |
| Variance (\(\sigma^2\)) | \(\frac{\sum x_i^2}{n} - (\bar{x})^2\) | \(\frac{200}{10} - (2)^2 = 20 - 4\) | 16 |
| Standard Deviation (\(\sigma\)) | \(\sqrt{\sigma^2}\) | \(\sqrt{16}\) | 4 |
| Coefficient of Variation (CV) | \(\frac{\sigma}{\bar{x}} \times 100\) | \(\frac{4}{2} \times 100\) | 200 |
Based on the calculations, the coefficient of variation is 200.
| Concept | Definition | Formula |
|---|---|---|
| Mean | The average value of a dataset. | \(\bar{x} = \frac{\sum x_i}{n}\) |
| Variance | A measure of how spread out the data points are from the mean (average of squared differences). | \(\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n}\) or \(\frac{\sum x_i^2}{n} - (\bar{x})^2\) |
| Standard Deviation | The square root of the variance; measures the typical distance of data points from the mean. | \(\sigma = \sqrt{\sigma^2}\) |
| Coefficient of Variation | A standardized measure of dispersion of a probability distribution or frequency distribution. | \(\text{CV} = \frac{\sigma}{\bar{x}} \times 100\%\) |
The coefficient of variation is a useful tool when comparing datasets with different scales or units. For example, it can be used to compare the variability in heights (measured in meters) and weights (measured in kilograms) within a population. A higher CV indicates greater variability relative to the mean, while a lower CV indicates less relative variability.
It is particularly valuable in fields like finance to compare the risk (measured by standard deviation) of investments with different expected returns (measured by the mean). A lower CV might indicate a more favorable risk-return trade-off.
However, the coefficient of variation should be used cautiously, especially when the mean (\( \bar{x} \)) is close to zero, as small changes in the mean can lead to large fluctuations in the CV.
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