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If \(\rm \sum x_i = 20, \sum x_i^2=200\)  and n = 10 for an observed variable x, then what is the coefficient of variation?

This question was previously asked in
NDA 2020 GAT Previous Year Paper (06-Sep-2020)
The correct answer is

200

Understanding the Coefficient of Variation

The coefficient of variation (CV) is a statistical measure of the relative variability of data. It is the ratio of the standard deviation to the mean, often expressed as a percentage. It helps compare the degree of variation between data sets, even if their means are drastically different.

Coefficient of Variation Formula

The formula for the coefficient of variation (CV) is:

\( \text{CV} = \frac{\sigma}{\bar{x}} \times 100\% \)

Where:

  • \( \sigma \) is the standard deviation
  • \( \bar{x} \) is the mean

To find the coefficient of variation, we first need to calculate the mean (\( \bar{x} \)) and the standard deviation (\( \sigma \)) from the given data.

Calculating the Mean (\( \bar{x} \))

The mean is the average of the observations. The formula for the mean is:

\( \bar{x} = \frac{\sum x_i}{n} \)

Given:

  • \( \sum x_i = 20 \)
  • \( n = 10 \)

Substitute the values into the formula:

\( \bar{x} = \frac{20}{10} \)

\( \bar{x} = 2 \)

So, the mean of the observed variable x is 2.

Calculating the Standard Deviation (\( \sigma \))

The standard deviation is the square root of the variance. The variance (\( \sigma^2 \)) can be calculated using the formula:

\( \sigma^2 = \frac{\sum x_i^2}{n} - (\bar{x})^2 \)

Given:

  • \( \sum x_i^2 = 200 \)
  • \( n = 10 \)
  • \( \bar{x} = 2 \) (calculated above)

Substitute the values into the variance formula:

\( \sigma^2 = \frac{200}{10} - (2)^2 \)

\( \sigma^2 = 20 - 4 \)

\( \sigma^2 = 16 \)

Now, calculate the standard deviation (\( \sigma \)) by taking the square root of the variance:

\( \sigma = \sqrt{\sigma^2} = \sqrt{16} \)

\( \sigma = 4 \)

The standard deviation is 4.

Calculating the Coefficient of Variation

Now that we have the standard deviation (\( \sigma = 4 \)) and the mean (\( \bar{x} = 2 \)), we can calculate the coefficient of variation:

\( \text{CV} = \frac{\sigma}{\bar{x}} \times 100 \)

\( \text{CV} = \frac{4}{2} \times 100 \)

\( \text{CV} = 2 \times 100 \)

\( \text{CV} = 200 \)

The coefficient of variation is 200. The options are given as numerical values without the percentage symbol, so the answer is 200.

Statistic Formula Calculation Result
Mean (\(\bar{x}\)) \(\frac{\sum x_i}{n}\) \(\frac{20}{10}\) 2
Variance (\(\sigma^2\)) \(\frac{\sum x_i^2}{n} - (\bar{x})^2\) \(\frac{200}{10} - (2)^2 = 20 - 4\) 16
Standard Deviation (\(\sigma\)) \(\sqrt{\sigma^2}\) \(\sqrt{16}\) 4
Coefficient of Variation (CV) \(\frac{\sigma}{\bar{x}} \times 100\) \(\frac{4}{2} \times 100\) 200

Final Coefficient of Variation Result

Based on the calculations, the coefficient of variation is 200.

Revision Table: Key Statistics Concepts

Concept Definition Formula
Mean The average value of a dataset. \(\bar{x} = \frac{\sum x_i}{n}\)
Variance A measure of how spread out the data points are from the mean (average of squared differences). \(\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n}\) or \(\frac{\sum x_i^2}{n} - (\bar{x})^2\)
Standard Deviation The square root of the variance; measures the typical distance of data points from the mean. \(\sigma = \sqrt{\sigma^2}\)
Coefficient of Variation A standardized measure of dispersion of a probability distribution or frequency distribution. \(\text{CV} = \frac{\sigma}{\bar{x}} \times 100\%\)

Additional Information: Using Coefficient of Variation

The coefficient of variation is a useful tool when comparing datasets with different scales or units. For example, it can be used to compare the variability in heights (measured in meters) and weights (measured in kilograms) within a population. A higher CV indicates greater variability relative to the mean, while a lower CV indicates less relative variability.

It is particularly valuable in fields like finance to compare the risk (measured by standard deviation) of investments with different expected returns (measured by the mean). A lower CV might indicate a more favorable risk-return trade-off.

However, the coefficient of variation should be used cautiously, especially when the mean (\( \bar{x} \)) is close to zero, as small changes in the mean can lead to large fluctuations in the CV.

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Similar Questions

  1. Mean of 100 observations is 50 and standard deviation is 10. If 5 is added to each observation, then what will be the new mean and new standard deviation respectively?

  2. If \(\rm \displaystyle \sum_{i = 1}^{10}x_i = 110\)  and  \(\rm \displaystyle \sum_{i = 1}^{10}x_i^2 = 1540\)   then what is the variance?

  3. The sum of deviations of n numbers from 10 and 20 are p and q respectively. If (p - q)2 = 10000, then what is the value of n?

  4. In any discrete series (when all values are not same) if x represent mean deviation about mean and y represent standard deviation, then which one of the following is correct?

  5. If V is the variance and M is the mean of first 15 natural numbers, then what is V + M 2equal to?

  6. Which one of the following subjects shows highest variability of marks ?

  7. What is the coefficient of variation of marks in Mathematics ?

  8. Arithmetic mean of 10 observations is 60 and sum of squares of deviations from 50 is 5000. What is the standard deviation of the observations?

  9. Consider the following statements:

    1) If 10 is added to each entry on a list, then the average increases by 10

    2) IF 10 is added to each entry on a list, then the standard deviation increases by 10

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    What of the above statements are correct?

  10. The variance of 25 observations is 4. If 2 is added to each observation, then the new variance of the resulting observations is


Important Questions from Variance and Standard Deviation

  1. Mean of 100 observations is 50 and standard deviation is 10. If 5 is added to each observation, then what will be the new mean and new standard deviation respectively?

  2. When sampling is done without replacement then standard error of mean is:

  3. Consider a population that is finite, and sampling is with replacement. If the variance of the population is 2176.8 with a sample size of 16, then the variance of the sampling distribution of means is:

  4. If \(\rm \displaystyle \sum_{i = 1}^{10}x_i = 110\)  and  \(\rm \displaystyle \sum_{i = 1}^{10}x_i^2 = 1540\)   then what is the variance?

  5. The sum of deviations of n numbers from 10 and 20 are p and q respectively. If (p - q)2 = 10000, then what is the value of n?

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