If \((x^2 + ax + 2) + (2x^2 - 3x - 2)\) becomes a monomial, find a.
3
Adding the two expressions: \((x^2 + ax + 2) + (2x^2 - 3x - 2) = 3x^2 + (a-3)x + 0\).
For the result to be a monomial (a single term), the coefficient of the x-term must vanish, since only the \(3x^2\) term would then remain.
So \(a - 3 = 0\), which gives \(a = 3\).
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