If \(a^{2x+1} = a^{11}\) where \(a > 0\) and \(a \neq 1\), find x.
5
Since the bases are equal (\(a > 0\) and \(a \neq 1\)), the exponents must be equal.
So \(2x + 1 = 11\).
Solving, \(2x = 10\), so \(x = 5\).
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