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If: \(+ \rightarrow \times,\ - \rightarrow \div,\ \times \rightarrow -,\ \div \rightarrow +\) Then evaluate: \((12 + 3)\times4 - (8\div2) + 6 =\,?\)

This question was previously asked in
SSC CHSL 2025 Tier 1 Question Paper (21-Nov-2025) (Shift 1)
The correct answer is

33.6

This is a symbol-substitution problem, so the first job is to rewrite every operator in the expression using the new meanings before any arithmetic is attempted.

The replacement rule is \(+\rightarrow\times\), \(-\rightarrow\div\), \(\times\rightarrow-\) and \(\div\rightarrow+\).

Applying it to \((12+3)\times4-(8\div2)+6\) turns each symbol in turn and gives the working line \((12\times3)-4\div(8+2)\times6\).

Clear the two easy pieces first: the product \(12\times3=36\) and the bracket \(8+2=10\).

Now the line reads \(36-4\div10\times6\), and BODMAS demands that the division and multiplication be done before the subtraction.

So \(4\div10=0.4\), then \(0.4\times6=2.4\), and finally \(36-2.4=33.6\).

The key idea is to swap the symbols first and only afterwards evaluate strictly by order of operations, never left to right. Hence the value is 33.6.

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