If the wavelengths corresponding to ultraviolet, visible and infrared radiations are given as λ UV ,λ VIS and λ IR respectively, then which one of the following gives the correct relationship among these wavelengths?
λ UV < λ VIS < λ IR
This question asks about the relationship between the wavelengths of three different types of electromagnetic radiation: ultraviolet (UV), visible (VIS), and infrared (IR) radiation. To answer this, we need to understand where these types of radiation fall within the electromagnetic spectrum.
The electromagnetic spectrum is a continuous range of all types of electromagnetic waves, ordered by frequency and wavelength. Different parts of the spectrum are given different names based on their characteristics and how they interact with matter.
The order of electromagnetic radiation types from longest wavelength to shortest wavelength is generally:
Wavelength (\(\lambda\)) and frequency (\(f\)) are inversely related for electromagnetic waves traveling in a vacuum or the same medium, according to the equation \(c = \lambda f\), where \(c\) is the speed of light. This means that as wavelength increases, frequency decreases, and vice versa.
Based on the order in the electromagnetic spectrum:
Therefore, comparing these three:
This gives us a clear order for the wavelengths:
Wavelength of Ultraviolet (\(\lambda_{UV}\)) < Wavelength of Visible (\(\lambda_{VIS}\)) < Wavelength of Infrared (\(\lambda_{IR}\))
Let's look at the given options and compare them to our finding:
The relationship \(\lambda_{UV} < \lambda_{VIS} < \lambda_{IR}\) correctly represents the relative wavelengths of ultraviolet, visible, and infrared radiation.
| Radiation Type | Approximate Wavelength Range | Relative Wavelength |
|---|---|---|
| Ultraviolet (UV) | 10 nm to 400 nm | Shortest among the three |
| Visible (VIS) | 400 nm to 700 nm | Middle range |
| Infrared (IR) | 700 nm to 1 mm | Longest among the three |
From the table and the position in the electromagnetic spectrum, it is clear that the wavelength order is Ultraviolet < Visible < Infrared.
The correct relationship between the wavelengths of ultraviolet (\(\lambda_{UV}\)), visible (\(\lambda_{VIS}\)), and infrared (\(\lambda_{IR}\)) radiation is \(\lambda_{UV} < \lambda_{VIS} < \lambda_{IR}\).
| Concept | Description | Relationship with Wavelength |
|---|---|---|
| Electromagnetic Spectrum | The range of all possible frequencies of electromagnetic radiation. | Ordered by wavelength and frequency. |
| Wavelength (\(\lambda\)) | The distance between successive crests or troughs of a wave. | Inversely proportional to frequency (\(f\)) in a given medium (\(c = \lambda f\)). |
| Frequency (\(f\)) | The number of wave cycles passing a point per unit time. | Inversely proportional to wavelength (\(\lambda\)). Higher frequency means shorter wavelength. |
| Energy | Related to frequency (\(E = hf\)). Higher frequency means higher energy. | Inversely related to wavelength (\(E = hc/\lambda\)). Shorter wavelength means higher energy. |
Understanding the properties of these radiation types is important:
The difference in wavelengths (and thus frequencies and energies) is what gives each type of radiation its unique properties and applications.
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