A person burned a firecracker in front of a cliff and heard its echo 5 s after it burst. The distance of the cliff from the person, if the speed of the sound is 340 m/s, is close to
This problem involves understanding how echoes work and applying the relationship between distance, speed, and time. An echo is produced when sound waves reflect off a surface, like a cliff. The time measured for the echo is the total time it takes for the sound to travel from the source (the person) to the reflecting surface (the cliff) and then back to the source (where the person hears the echo).
Let the distance from the person to the cliff be \(d\). The sound travels this distance \(d\) towards the cliff and then travels the same distance \(d\) back as an echo. So, the total distance traveled by the sound for the echo is \(2d\).
The formula relating distance, speed, and time is:
\(\text{Distance} = \text{Speed} \times \text{Time}\)
In this case, the total distance is \(2d\) and the time is the round trip time \(t\). So, we have:
\(2d = v \times t\)
To find the distance to the cliff (\(d\)), we rearrange the formula:
\(d = \frac{v \times t}{2}\)
Substitute the given values into the formula:
\(d = \frac{340 \text{ m/s} \times 5 \text{ s}}{2}\)
First, calculate the product of speed and time:
\(v \times t = 340 \text{ m/s} \times 5 \text{ s} = 1700 \text{ m}\)
This 1700 m is the total distance the sound traveled (to the cliff and back). Now, divide by 2 to find the distance to the cliff:
\(d = \frac{1700 \text{ m}}{2}\)
\(d = 850 \text{ m}\)
The distance of the cliff from the person is 850 meters.
| Quantity | Symbol | Value |
|---|---|---|
| Speed of Sound | \(v\) | 340 m/s |
| Echo Time (Round Trip) | \(t\) | 5 s |
| Distance to Cliff | \(d\) | ? |
| Formula Used | Calculation | Result |
|---|---|---|
| \(d = \frac{v \times t}{2}\) | \(d = \frac{340 \text{ m/s} \times 5 \text{ s}}{2}\) | \(d = 850 \text{ m}\) |
| Concept | Description |
|---|---|
| Echo | Reflection of sound waves off a surface. |
| Echo Time | The total time taken for sound to travel from the source to the reflector and back. |
| Total Distance for Echo | Twice the distance from the source to the reflector (\(2d\)). |
| Formula | \(2d = \text{Speed} \times \text{Time}\) or \(d = \frac{\text{Speed} \times \text{Time}}{2}\) |
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