If the third proportional to two numbers is 32 and the second number is 16, find the first number.
8
If \(c\) is the third proportional to \(a\) and \(b\), then \(a : b = b : c\), which gives \(c = \dfrac{b^2}{a}\).
Here the second number \(b = 16\) and the third proportional \(c = 32\).
Substitute into the relation: \(32 = \dfrac{16^2}{a} = \dfrac{256}{a}\).
Solve for \(a\): \(a = \dfrac{256}{32} = 8\).
Hence, the first number is 8.
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