If the occurrence of events follows Poisson Process with mean rate λ, then inter-occurence time of events will follow:
Exponential distribution
In a Poisson process with rate \(\lambda\), the probability of no event in time \(t\) is \(P(T>t)=e^{-\lambda t}\), so the inter-arrival time \(T\) has density \(f(t)=\lambda e^{-\lambda t}\) for \(t\ge 0\) — the Exponential distribution with parameter \(\lambda\).
The Poisson distribution counts the number of events in a fixed interval (not the gap); the Gamma distribution gives the time until the \(k\)-th event (general case), and Geometric is a discrete analogue. For a single inter-occurrence time the answer is Exponential distribution.
The memory-less property is followed by which of the following continuous distribution:
A Poisson distribution has a double mode at x = 1 and x = 2. The probability for x = 1 or for x = 2 of these two value is:
If a discrete random variable X follows uniform distribution and assume only the values 8, 9, 11, 15, 18, 20, the value of P(|X - 14| < 5) will be:
The probability density function of a random variable X is f(x) = \(\frac{\pi}{10} sin \frac{\pi x}{5}\) ; 0 ≤ x ≤ 5. The first quartile of X is:
The mode of a geometric distribution with parameter p is:
If ten coins are tossed simultaneously, then the probability of getting at most 1 head is:
The PDF of babies’ age is defined as \(f(x)=\dfrac{3}{4}x(2-x);0<x<2\) , The 5 th decile point of X is:
The interquartile range of continuous random variable X having PDF f(x) = e -x ; x ≥ 0 is:
Patients arrive at a clinic following the Poisson process, with the mean rate of 10 customers per hour. The inter-arrival time of a customer follows:
The length of time X, needed by an examinee of competition to complete a 1-hour exam, is a random variable with
PDF \(f(x)=\dfrac{6}{5}(x^2+x);0 \le x \le 1.\) , The value of F(0.5) is:
The square of a standard normal variate is a
The memory-less property is followed by which of the following continuous distribution:
A Poisson distribution has a double mode at x = 1 and x = 2. The probability for x = 1 or for x = 2 of these two value is:
If a discrete random variable X follows uniform distribution and assume only the values 8, 9, 11, 15, 18, 20, the value of P(|X - 14| < 5) will be:
The probability density function of a random variable X is f(x) = \(\frac{\pi}{10} sin \frac{\pi x}{5}\) ; 0 ≤ x ≤ 5. The first quartile of X is: