If the arithmetic mean is 25 and geometric mean is 15, then the value of the Harmonic mean is equal to:
9
The harmonic mean (H) is related to the arithmetic mean (A) and the geometric mean (G) by the following formula:
H = 3 / (1/A + 1/G).
Given that the arithmetic mean is 25 and the geometric mean is 15, we can calculate the harmonic mean:
H = 3 / (1/25 + 1/15) = 9.
Similar Questions
Out of 100 numbers, 20 are 4's, 40 are 5's, 30 are 6's, and the remaining are 7's. The arithmetic mean of the numbers is:
The median of the normal distribution with mean and variance \(\mu\) and \(\sigma^2\) is:
Let a continuous random variable \( X \) have probability density function (pdf):
\[f(x) = \begin{cases} -0.75 \, x^2 + 1.5x & \text{for } 0 < x < 2 \\ 0, & \text{otherwise} \end{cases}\]
Find the mode of \( X \).
Important Questions from Mean and Variance of Random variables
X is a non-negative integer valued random variable with
\( P(X = x) =\left\{ \begin{matrix} \dfrac {x+1}{2^{(x+2)}} & x = 0, 1, 2... \\\ 0 & \rm{otherwise} \end{matrix} \right.\)
Then, mean and variance of X are respectively
Out of 100 numbers, 20 are 4's, 40 are 5's, 30 are 6's, and the remaining are 7's. The arithmetic mean of the numbers is:
The median of the normal distribution with mean and variance \(\mu\) and \(\sigma^2\) is:
Let a continuous random variable \( X \) have probability density function (pdf):
\[f(x) = \begin{cases} -0.75 \, x^2 + 1.5x & \text{for } 0 < x < 2 \\ 0, & \text{otherwise} \end{cases}\]
Find the mode of \( X \).
A random variable X has the distribution law as given below:
X
1
2
3
P(X = x)
0.3
0.4
0.3
The variance of the distribution is:
