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Question

If $\tan A + \sec A = 3$, find $\tan A$.

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is

$\frac{4}{3}$

Solving Trigonometric Equations: Finding \(\tan A\)

We are given the equation \(\tan A + \sec A = 3\) and need to find the value of \(\tan A\).

Key Trigonometric Identity

We will use the fundamental trigonometric identity relating \(\sec A\) and \(\tan A\):

\(\sec^2 A - \tan^2 A = 1\)

This identity can be factored as a difference of squares:

\((\sec A - \tan A)(\sec A + \tan A) = 1\)

Step-by-Step Solution

  1. Substitute the given value: We know that \(\sec A + \tan A = 3\). Substitute this into the factored identity:

    \((\sec A - \tan A)(3) = 1\)

  2. Find \(\sec A - \tan A\): Divide both sides by 3:

    \(\sec A - \tan A = \frac{1}{3}\)

  3. Set up a system of equations: Now we have two equations:

    • Equation 1: \(\sec A + \tan A = 3\)
    • Equation 2: \(\sec A - \tan A = \frac{1}{3}\)
  4. Solve for \(\tan A\): Subtract Equation 2 from Equation 1 to eliminate \(\sec A\):

    \((\sec A + \tan A) - (\sec A - \tan A) = 3 - \frac{1}{3}\)

    \(\sec A + \tan A - \sec A + \tan A = \frac{9}{3} - \frac{1}{3}\)

    \(2 \tan A = \frac{8}{3}\)

  5. Calculate the final value: Divide by 2:

    \(\tan A = \frac{8}{3} \times \frac{1}{2}\)

    \(\tan A = \frac{4}{3}\)

Conclusion

The value of \(\tan A\) is \(\frac{4}{3}\).

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Important Questions from Trigonometric Ratios and Identities

  1. What is the ratio of the greatest to the smallest value of 2 – 2 sin x – sin 2x, 0 ≤ x ≤ (π/2)? 

  2. If sinθ = \(\frac{4}{5}\) , Find the value of sin3θ

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  4. What is (1 + cot θ - cosec θ)(1 + tan θ + sec θ) equal to?

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