If sec θ + cos θ = 32, then sec2 θ+ cos2 θ is ______.
1022
We are given the equation \(\sec \theta + \cos \theta = 32\) and asked to find the value of \(\sec^2 \theta + \cos^2 \theta\).
To find \(\sec^2 \theta + \cos^2 \theta\), we can consider squaring the given equation. Remember the algebraic identity: \((a+b)^2 = a^2 + 2ab + b^2\).
Let's square both sides of the equation \(\sec \theta + \cos \theta = 32\):
\((\sec \theta + \cos \theta)^2 = (32)^2\)
Applying the identity on the left side:
\(\sec^2 \theta + 2(\sec \theta)(\cos \theta) + \cos^2 \theta = 32^2\)
Now, let's simplify the term \((\sec \theta)(\cos \theta)\). We know that the secant function is the reciprocal of the cosine function. That is, \(\sec \theta = \frac{1}{\cos \theta}\).
So, \((\sec \theta)(\cos \theta) = \left(\frac{1}{\cos \theta}\right)(\cos \theta)\).
Assuming \(\cos \theta \neq 0\), the term simplifies to:
\((\sec \theta)(\cos \theta) = 1\)
Substitute this value back into the squared equation:
\(\sec^2 \theta + 2(1) + \cos^2 \theta = 32^2\)
\(\sec^2 \theta + 2 + \cos^2 \theta = 1024\)
Now, rearrange the equation to isolate the term we want to find, \(\sec^2 \theta + \cos^2 \theta\):
\(\sec^2 \theta + \cos^2 \theta = 1024 - 2\)
\(\sec^2 \theta + \cos^2 \theta = 1022\)
Thus, the value of \(\sec^2 \theta + \cos^2 \theta\) is 1022.
| Option | Value | Matches Calculation? |
|---|---|---|
| 1 | 1022 | Yes |
| 2 | 1000 | No |
| 3 | 1024 | No |
| 4 | 1020 | No |
The calculated value 1022 matches Option 1.
| Concept | Definition/Identity | Notes |
|---|---|---|
| Secant Function | \(\sec \theta = \frac{1}{\cos \theta}\) | Reciprocal of cosine |
| Cosine Function | \(\cos \theta\) | Ratio of adjacent side to hypotenuse in a right triangle |
| Algebraic Identity | \((a+b)^2 = a^2 + 2ab + b^2\) | Useful for squaring sums |
Reciprocal identities in trigonometry relate the six trigonometric functions to each other. They are fundamental for simplifying expressions and solving equations.
In this problem, the identity \(\sec \theta \cdot \cos \theta = 1\) (derived from \(\sec \theta = 1/\cos \theta\)) was crucial for simplifying the middle term after squaring the expression.
These identities are often used in combination with Pythagorean identities (\(\sin^2 \theta + \cos^2 \theta = 1\), etc.) and other trigonometric formulas to solve a wide range of problems.
Evaluate the following.
sin 25° sin 65° – cos 25° cos 65°.
If sin 23° = \(\frac{a}{b}\), then the value of sec 23° - sin 67° is __________.
If sec2 θ + tan2 θ = \(\frac{25}{18}\), then the value of sec4 θ - tan4 θ is:
If \(\frac{\cos \beta}{\sec \alpha}\) = 15 and \(\frac{\sin \beta}{\sec \alpha}\) = 16, then the value of sin2β is ___________.
If sec θ + tan θ = 5, (θ ≠ 0), then sec θ is equal to:
If sin t + cos t = \(\frac{4}{5}\), then find sin t. cos t.
Select the INCORRECT formula from the following options.
If Sin θ = \(\frac{4}{5}\), find the value of tan θ - Cot θ.
If a cot θ + b cosec θ = p and b cot θ + a cosec θ = q then p2 - q2 is equal to ______.
The value of 4 sin 230° + 3 cot 260° - 2 tan 245° is:
The value of 1 - sin 35° cos 55° is equal to:
If sin 3 θ = cos ( θ – 6°), then θ is:
If θ = 45°, then what will be the value of \(\frac{{\\sin \,\theta \, + \,\cos \,\theta }}{{\sin \,\theta \, - \,\cos \,\theta }}\) ?
If sin A = \(\frac{1}{2}\) and cos B = \(\frac{1}{2}\) then find A + B.