If numerator of a fraction is increased by 25% and the denominator is decreased by 15%, the fraction becomes 15/17. Find the value of the original fraction?
3/5
Let the original fraction be x/y.
The numerator is increased by 25%, so the new numerator = x × (125/100) = 1.25x.
The denominator is decreased by 15%, so the new denominator = y × (85/100) = 0.85y.
The new fraction equals 15/17, so:
1.25x / 0.85y = 15/17
This can be written as (x/y) × (1.25/0.85) = 15/17
Simplify 1.25/0.85 = 125/85 = 25/17
So (x/y) × (25/17) = 15/17
Multiply both sides by 17: (x/y) × 25 = 15
x/y = 15/25 = 3/5
So the original fraction is 3/5
Consider following sums of fractions:
A. 16/19 + 1/4
B. 11/14 + 1/5
C. 19/21 + 1/3
Choose the correct ascending order of above sums of fractions from the following options:
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: