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Question

If numerator of a fraction is increased by 25% and the denominator is decreased by 15%, the fraction becomes 15/17. Find the value of the original fraction?

This question was previously asked in
UGC NET 2023 Home Science Question Paper (13-Dec-2023) (Shift 1)
The correct answer is

3/5

Let the original fraction be x/y.
The numerator is increased by 25%, so the new numerator = x × (125/100) = 1.25x.
The denominator is decreased by 15%, so the new denominator = y × (85/100) = 0.85y.
The new fraction equals 15/17, so:
1.25x / 0.85y = 15/17
This can be written as (x/y) × (1.25/0.85) = 15/17
Simplify 1.25/0.85 = 125/85 = 25/17
So (x/y) × (25/17) = 15/17
Multiply both sides by 17: (x/y) × 25 = 15
x/y = 15/25 = 3/5
So the original fraction is 3/5

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Similar Questions

  1. Consider following sums of fractions:
    A. 16/19 + 1/4
    B. 11/14 + 1/5
    C. 19/21 + 1/3
    Choose the correct ascending order of above sums of fractions from the following options:


Important Questions from Fractions

  1. Which fraction among the following is the least ?

    \(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)

  2. Find the value of the following expression:

    \(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)

  3. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  4. If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:

  5. The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)  is:

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