If numerator of a fraction is increased by 25% and the denominator is decreased by 15%, the fraction becomes 15/17. Find the value of the original fraction?
3/5
Let the original fraction be x/y.
The numerator is increased by 25%, so the new numerator = x × (125/100) = 1.25x.
The denominator is decreased by 15%, so the new denominator = y × (85/100) = 0.85y.
The new fraction equals 15/17, so:
1.25x / 0.85y = 15/17
This can be written as (x/y) × (1.25/0.85) = 15/17
Simplify 1.25/0.85 = 125/85 = 25/17
So (x/y) × (25/17) = 15/17
Multiply both sides by 17: (x/y) × 25 = 15
x/y = 15/25 = 3/5
So the original fraction is 3/5
Similar Questions
Consider following sums of fractions:
A. $\frac{16}{19}$ + $\frac{1}{4}$
B. $\frac{11}{14}$ + $\frac{1}{5}$
C. $\frac{19}{21}$ + $\frac{1}{3}$
Choose the correct ascending order of above sums of fractions from the following options:
Important Questions from Fractions
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I
Column II
a.
Equivalent fraction of \(\frac{7}{12}\) is
i.
Proper fraction
b.
Equivalent fraction of \(\frac{9}{15}\) is
ii.
Improper fraction
c.
\(\frac{7}{11}\) is
iii.
\(\frac{21}{36}\)
d.
\(\frac{19}{5}\) is
iv.
\(\frac{3}{5}\)
Among the fractions \(\frac{7}{12}\) , \(\frac{8}{15}\) , \(\frac{17}{24}\) and \(\frac{13}{18}\) , which is the smallest?
