If numerator of a fraction is increased by 25% and the denominator is decreased by 15%, the fraction becomes 15/17. Find the value of the original fraction?
3/5
Let the original fraction be x/y.
The numerator is increased by 25%, so the new numerator = x × (125/100) = 1.25x.
The denominator is decreased by 15%, so the new denominator = y × (85/100) = 0.85y.
The new fraction equals 15/17, so:
1.25x / 0.85y = 15/17
This can be written as (x/y) × (1.25/0.85) = 15/17
Simplify 1.25/0.85 = 125/85 = 25/17
So (x/y) × (25/17) = 15/17
Multiply both sides by 17: (x/y) × 25 = 15
x/y = 15/25 = 3/5
So the original fraction is 3/5
Similar Questions
Consider following sums of fractions:
A. $\frac{16}{19}$ + $\frac{1}{4}$
B. $\frac{11}{14}$ + $\frac{1}{5}$
C. $\frac{19}{21}$ + $\frac{1}{3}$
Choose the correct ascending order of above sums of fractions from the following options:
Important Questions from Fractions
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
The value of \(\frac{5}{8}÷ (\frac{8}{11}\times2\frac{3}{4}÷\frac{4}{9})\) + \(5\frac{1}{3}\) ÷ \((5\frac{1}{4}\div\frac{3}{8}\times\frac{3}{7}) \) of \(1\frac{7}{9}\) is:
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
