Consider following sums of fractions:
A. $\frac{16}{19}$ + $\frac{1}{4}$
B. $\frac{11}{14}$ + $\frac{1}{5}$
C. $\frac{19}{21}$ + $\frac{1}{3}$
Choose the correct ascending order of above sums of fractions from the following options:
B < A < C
To compare the three sums, convert each pair of fractions to a single fraction or decimal so they can be directly compared.
Sum A: 16/19 + 1/4 = (16 × 4 + 1 × 19)/(19 × 4) = (64 + 19)/76 = 83/76 ≈ 1.092.
Sum B: 11/14 + 1/5 = (11 × 5 + 1 × 14)/(14 × 5) = (55 + 14)/70 = 69/70 ≈ 0.986.
Sum C: 19/21 + 1/3 = (19 × 3 + 1 × 21)/(21 × 3) = (57 + 21)/63 = 78/63 = 26/21 ≈ 1.238.
Comparing the decimal values: B ≈ 0.986 is the smallest, A ≈ 1.092 is the middle value, and C ≈ 1.238 is the largest.
Therefore, the correct ascending order of the sums is B < A < C.
Similar Questions
If numerator of a fraction is increased by 25% and the denominator is decreased by 15%, the fraction becomes 15/17. Find the value of the original fraction?
Important Questions from Fractions
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I
Column II
a.
Equivalent fraction of \(\frac{7}{12}\) is
i.
Proper fraction
b.
Equivalent fraction of \(\frac{9}{15}\) is
ii.
Improper fraction
c.
\(\frac{7}{11}\) is
iii.
\(\frac{21}{36}\)
d.
\(\frac{19}{5}\) is
iv.
\(\frac{3}{5}\)
Among the fractions \(\frac{7}{12}\) , \(\frac{8}{15}\) , \(\frac{17}{24}\) and \(\frac{13}{18}\) , which is the smallest?
