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If $\lambda = 0$, is an eigen values of A, then $\det(A)$ is :

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CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
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Eigenvalue and Determinant Relationship

An eigenvalue ($\lambda$) of a square matrix $A$ is a scalar that satisfies the characteristic equation: $ \det(A - \lambda I) = 0 $ where $I$ is the identity matrix of the same dimension as $A$.

Applying the Given Eigenvalue

We are given that $\lambda = 0$ is an eigenvalue of matrix $A$. Substituting $\lambda = 0$ into the characteristic equation gives:

$ \det(A - 0 \cdot I) = 0 $

Deriving the Determinant

Simplifying the expression inside the determinant:

$ A - 0 \cdot I = A $

Therefore, the characteristic equation becomes:

$ \det(A) = 0 $

This shows that if 0 is an eigenvalue of a matrix $A$, its determinant must be 0.

Conclusion

Hence, if $\lambda = 0$ is an eigenvalue of $A$, then $\det(A)$ is 0.

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