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If $A \in R_{n \times n}$; $\det A=0$, then :
A. A is non singular and the rows and columns of A are linearly independent
B. A is non-singular and the rows and columns of A are linearly dependent
C. A is non-singular and A has one zero rows
D. A is singular
E. A is singular and rows and columns of A are linearly dependent
Choose the correct answer from the options given below :

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
A only

Matrix Determinant Condition Analysis

We are given a square matrix $A$ of size $n \times n$ from the set of real numbers ($A \in R_{n \times n}$). The key information provided is that the determinant of this matrix is zero.

The condition is stated as: $ \det A = 0 $

Singular Matrix Definition

In linear algebra, the determinant of a matrix provides critical information about its properties. Specifically:

  • A square matrix is defined as singular if its determinant is exactly zero.
  • Conversely, a square matrix is non-singular (or invertible) if its determinant is non-zero.

Deriving Matrix Properties

Given that $\det A = 0$, the matrix $A$ must be singular according to the definition.

Evaluating Multiple Choice Options

Let's analyze the options based on the fact that $A$ is singular:

  • Option A states "A is non singular...". This contradicts $\det A = 0$.
  • Option B states "A is non-singular...". This also contradicts $\det A = 0$.
  • Option C states "A is non-singular...". This contradicts $\det A = 0$.
  • Option D states "A is singular". This aligns perfectly with the condition $\det A = 0$.
  • Option E states "A is singular and rows and columns of A are linearly dependent". While this statement is factually true for a singular matrix, Option D is the most direct and fundamental conclusion derived solely from $\det A = 0$.

Final Conclusion

The condition $\det A = 0$ directly and solely implies that the matrix $A$ is singular.

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