The problem requires finding a digit, represented by '*', that makes the number 7235* divisible by 11. We will use the standard divisibility rule for 11 to find this digit.
A number is divisible by 11 if the alternating sum of its digits is zero or a multiple of 11. This means we calculate the difference between the sum of digits at odd positions and the sum of digits at even positions (counting from the right).
Let the number be represented as 7235*, where '*' is the unknown digit.
| Digit | 7 | 2 | 3 | 5 | * |
| Position (from right) | 5 (Odd) | 4 (Even) | 3 (Odd) | 2 (Even) | 1 (Odd) |
Sum of digits at odd positions: The digits are *, 3, and 7. Let the unknown digit '*' be represented by the variable $x$. Their sum is $S_{odd} = x + 3 + 7 = x + 10$.
Sum of digits at even positions: The digits are 5 and 2. Their sum is $S_{even} = 5 + 2 = 7$.
For the number to be divisible by 11, the difference $S_{odd} - S_{even}$ must be equal to 0 or a multiple of 11.
Difference = $(x + 10) - 7 = x + 3$.
We need to find a digit $x$ (where $0 \le x \le 9$) such that $x + 3$ is 0 or a multiple of 11. Let's check the possibilities:
This gives $x = -3$. This is not a valid digit (must be 0-9).
This gives $x = 11 - 3 = 8$. This is a valid digit (0-9).
This gives $x = 22 - 3 = 19$. This is not a valid digit.
Therefore, the only possible digit value for '*' (represented by $x$) is 8.
The missing digit '*' in the number 7235* must be 8 for the number to be divisible by 11. The number is 72358.
Verification: We can check the alternating sum: $7 - 2 + 3 - 5 + 8 = 11$. Since 11 is divisible by 11, our result is correct.
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