The question asks us to determine a number that will always divide a new number formed by rearranging the digits of 468312 in descending order. We are given that the original number, 468312, is divisible by 57.
First, let's verify the given information. The number is 468312. The divisor is 57. Note that $57 = 3 \times 19$. A number is divisible by 57 if it is divisible by both 3 and 19.
Since 468312 is divisible by both 3 and 19, it is indeed divisible by 57. ($468312 \div 57 = 8216$).
The digits in the number 468312 are 4, 6, 8, 3, 1, 2. Rearranging these digits in descending order gives the number 864321.
We need to find which of the given options (2, 3, 19, 17) will always divide the rearranged number 864321. The key is that the divisibility property must hold true for *any* rearrangement, but specifically, we are checking the descending order rearrangement.
Based on the analysis, the only number from the options that is guaranteed to divide the number formed by rearranging the digits of 468312 in descending order (864321) is 3. This is because the divisibility by 3 depends solely on the sum of the digits, which remains constant regardless of the order of the digits.
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