If \(\sqrt{a} + \sqrt{b} = 5\) and \(\sqrt{a} - \sqrt{b} = 1\), what are the values of a and b?
\(a = 9,\ b = 4\)
Add the two equations:
\((\sqrt{a} + \sqrt{b}) + (\sqrt{a} - \sqrt{b}) = 5 + 1 \Rightarrow 2\sqrt{a} = 6 \Rightarrow \sqrt{a} = 3 \Rightarrow a = 9\).
Subtract the second from the first:
\(2\sqrt{b} = 5 - 1 = 4 \Rightarrow \sqrt{b} = 2 \Rightarrow b = 4\).
Hence \(a = 9,\ b = 4\).
Rationalize:
$\frac{\sqrt{2}+\sqrt{3}}{\sqrt{2}-\sqrt{3}}$
The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\) is 5 × 10 k , where the value of k is :
Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)
If √625 = 25; then√(.00000625/25)is:
A. 0.0025
B. 0.001
C. 0.0001
D. 0.0005Find the value of:
\(\sqrt{150}-\sqrt{54}-\sqrt{24}\)
If \(\sqrt{4624}=68\) , then the value of:
\(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)