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Question

Simplify:

$\sqrt{3}(\sqrt{12} - \sqrt{27})$

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
-3

Simplify Radical Expression: $\\sqrt{3}(\sqrt{12} - \sqrt{27})$

The goal is to simplify the given mathematical expression involving square roots.

Step 1: Simplify Terms Inside Parentheses

First, simplify the square roots $\sqrt{12}$ and $\sqrt{27}$:

  • $\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}$
  • $\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \times \sqrt{3} = 3\sqrt{3}$

Step 2: Substitute Simplified Terms

Substitute these simplified forms back into the original expression:

$\sqrt{3}(2\sqrt{3} - 3\sqrt{3})$

Step 3: Combine Like Terms

Combine the terms inside the parentheses:

$2\sqrt{3} - 3\sqrt{3} = (2-3)\sqrt{3} = -1\sqrt{3} = -\sqrt{3}$

Step 4: Final Calculation

Now, multiply the term outside the parentheses by the simplified term inside:

$\sqrt{3} \times (-\sqrt{3})$

This simplifies to:

$-\sqrt{3} \times \sqrt{3} = -(\sqrt{3})^2 = -3$

The simplified value of the expression is -3.

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Important Questions from Surds and Indices

  1. The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\)  is 5 × 10 , where the value of k is :

  2. Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)

  3. If √625 = 25; then√(.00000625/25)is:

    A. 0.0025

    B. 0.001

    C. 0.0001

    D. 0.0005
  4. Find the value of:

    \(\sqrt{150}-\sqrt{54}-\sqrt{24}\)

  5. If \(\sqrt{4624}=68\) , then the value of:

    \(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)

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