$\sqrt{3}(\sqrt{12} - \sqrt{27})$
The goal is to simplify the given mathematical expression involving square roots.
First, simplify the square roots $\sqrt{12}$ and $\sqrt{27}$:
Substitute these simplified forms back into the original expression:
$\sqrt{3}(2\sqrt{3} - 3\sqrt{3})$
Combine the terms inside the parentheses:
$2\sqrt{3} - 3\sqrt{3} = (2-3)\sqrt{3} = -1\sqrt{3} = -\sqrt{3}$
Now, multiply the term outside the parentheses by the simplified term inside:
$\sqrt{3} \times (-\sqrt{3})$
This simplifies to:
$-\sqrt{3} \times \sqrt{3} = -(\sqrt{3})^2 = -3$
The simplified value of the expression is -3.
Rationalize:
$\frac{\sqrt{2}+\sqrt{3}}{\sqrt{2}-\sqrt{3}}$
Simplify: \(\sqrt{7+4\sqrt{3}}\)
The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\) is 5 × 10 k , where the value of k is :
Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)
If √625 = 25; then√(.00000625/25)is:
A. 0.0025
B. 0.001
C. 0.0001
D. 0.0005Find the value of:
\(\sqrt{150}-\sqrt{54}-\sqrt{24}\)
If \(\sqrt{4624}=68\) , then the value of:
\(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)