If √625 = 25; then√(.00000625/25)is: A. 0.0025 B. 0.001 C. 0.0001
D
We are asked to find the value of the expression \( \sqrt{\frac{0.00000625}{25}} \), given that \( \sqrt{625} = 25 \).
Let's break down the problem step-by-step:
The expression inside the square root is \( \frac{0.00000625}{25} \).
We can rewrite the numerator \( 0.00000625 \) in scientific notation or as a fraction to make the division easier. Note that \( 0.00000625 \) has 8 decimal places.
\( 0.00000625 = \frac{625}{100,000,000} = \frac{625}{10^8} \)
Now, the division becomes:
\( \frac{0.00000625}{25} = \frac{\frac{625}{10^8}}{25} = \frac{625}{10^8 \times 25} \)
We know that \( \frac{625}{25} = 25 \). So, the expression simplifies to:
\( \frac{25}{10^8} \)
In decimal form, \( \frac{25}{10^8} = 25 \times 10^{-8} = 0.00000025 \).
So, the expression inside the square root is \( 0.00000025 \).
Now we need to find \( \sqrt{0.00000025} \).
We know that \( \sqrt{25} = 5 \).
The number \( 0.00000025 \) has 8 decimal places. When we take the square root of a number with a certain number of decimal places, the result will have half that number of decimal places.
Half of 8 is 4.
So, \( \sqrt{0.00000025} \) will be a number with the digit 5 and 4 decimal places.
This number is \( 0.0005 \).
Alternatively, using scientific notation:
\( \sqrt{0.00000025} = \sqrt{25 \times 10^{-8}} \)
Using the property \( \sqrt{ab} = \sqrt{a} \times \sqrt{b} \):
\( \sqrt{25 \times 10^{-8}} = \sqrt{25} \times \sqrt{10^{-8}} \)
We know \( \sqrt{25} = 5 \).
And \( \sqrt{10^{-8}} = (10^{-8})^{\frac{1}{2}} = 10^{-8 \times \frac{1}{2}} = 10^{-4} \).
So, the result is \( 5 \times 10^{-4} \).
Converting this back to decimal form: \( 5 \times 10^{-4} = 0.0005 \).
Thus, \( \sqrt{\frac{0.00000625}{25}} = 0.0005 \).
Our calculated value \( 0.0005 \) matches option D.
| Calculation Step | Value |
|---|---|
| Expression | \( \sqrt{\frac{0.00000625}{25}} \) |
| Numerator as fraction | \( \frac{625}{10^8} \) |
| Fraction inside root | \( \frac{625/10^8}{25} = \frac{25}{10^8} = 0.00000025 \) |
| Square root of fraction | \( \sqrt{0.00000025} \) |
| Final Result | \( 0.0005 \) |
| Concept | Explanation | Example |
|---|---|---|
| Square Root Definition | The square root of a number \(x\) is a number \(y\) such that \(y^2 = x\). | \( \sqrt{25} = 5 \) because \( 5^2 = 25 \). |
| Square Root of Powers of 10 | \( \sqrt{10^{-n}} = 10^{-n/2} \). The power is halved. | \( \sqrt{10^{-8}} = 10^{-4} \). |
| Square Root of Decimals | Count the decimal places in the original number. The square root will have half that number of decimal places. | \( \sqrt{0.0025} \): 4 decimal places. \( \sqrt{25}=5 \). Result has 4/2=2 decimal places: \( 0.05 \). |
Dividing decimal numbers can sometimes be tricky. A simple method is to remove the decimal places by multiplying both the numerator and the denominator by a power of 10. In our case, we divided \(0.00000625\) by \(25\).
\( \frac{0.00000625}{25} \)
To remove the decimal from the numerator, multiply both numerator and denominator by \(10^8\):
\( \frac{0.00000625 \times 10^8}{25 \times 10^8} = \frac{625}{25 \times 10^8} \)
Now, perform the integer division \( \frac{625}{25} = 25 \).
So, the expression becomes \( \frac{25}{10^8} \). This is the same result obtained earlier, \( 0.00000025 \).
Understanding how to manipulate decimals and powers of 10 is crucial for solving such problems efficiently.
The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\) is 5 × 10 k , where the value of k is :
Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)
Find the value of:
\(\sqrt{150}-\sqrt{54}-\sqrt{24}\)
If \(\sqrt{4624}=68\) , then the value of:
\(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)
The value of √0.0144 is:
A. 0.12
B. 0.012
C. 1.2
D. 0.0012