$\sqrt{12} + \sqrt{75}$
The goal is to simplify the expression $\sqrt{12} + \sqrt{75}$ by simplifying each square root term first.
Find the largest perfect square that divides 12. The largest perfect square factor of 12 is 4 ($2^2 = 4$).
So, $\sqrt{12} = 2\sqrt{3}$.
Find the largest perfect square that divides 75. The largest perfect square factor of 75 is 25 ($5^2 = 25$).
So, $\sqrt{75} = 5\sqrt{3}$.
Now substitute the simplified terms back into the original expression:
$\sqrt{12} + \sqrt{75} = 2\sqrt{3} + 5\sqrt{3}$
Since both terms contain $\sqrt{3}$, they are like terms. Add the coefficients (the numbers in front of the radical):
$(2 + 5)\sqrt{3} = 7\sqrt{3}$
The simplified form of $\sqrt{12} + \sqrt{75}$ is $7\sqrt{3}$.
Rationalize:
$\frac{\sqrt{2}+\sqrt{3}}{\sqrt{2}-\sqrt{3}}$
Simplify: \(\sqrt{7+4\sqrt{3}}\)
The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\) is 5 × 10 k , where the value of k is :
Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)
If √625 = 25; then√(.00000625/25)is:
A. 0.0025
B. 0.001
C. 0.0001
D. 0.0005Find the value of:
\(\sqrt{150}-\sqrt{54}-\sqrt{24}\)
If \(\sqrt{4624}=68\) , then the value of:
\(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)