If a 7-digit number 48085A7 is completely divisible by 3, what is the least value of A?
1
A number is divisible by 3 if the sum of its digits is divisible by 3.
Sum of digits \(= 4+8+0+8+5+A+7 = 32+A\).
For \(32+A\) to be divisible by 3, \(A\) must be 1, 4, or 7 (since \(32 \equiv 2 \pmod 3\), we need \(A \equiv 1 \pmod 3\)).
The least such value of A is 1.
Hence, the least value of A is 1.
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