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Question

What is the least value that must be assigned to A so that the 8-digit number 910A3076 is divisible by 6?

This question was previously asked in
RRB Group D 2025 Question Paper (18-Aug-2026) (Shift 1)
The correct answer is

1

A number is divisible by 6 if it is divisible by both 2 and 3.

The last digit is 6, so the number is divisible by 2 for any A.

Sum of digits = 9 + 1 + 0 + A + 3 + 0 + 7 + 6 = 26 + A, which must be a multiple of 3.

The least digit making 26 + A a multiple of 3 is A = 1 (sum = 27).

Hence, the answer is 1.

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  1. If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?

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