What is the value that must be assigned to A so that the 8-digit number 753A3228 is divisible by 18?
6
A number is divisible by 18 if it is divisible by both 2 and 9. The number 753A3228 is even, so it is already divisible by 2.
For divisibility by 9, the sum of digits must be a multiple of 9: 7+5+3+A+3+2+2+8 = 30 + A. For this to be a multiple of 9, A = 6 (giving 36).
Hence, this is the correct answer.
Similar Questions
What is the least value that must be assigned to A so that the 8-digit number 796A6351 is divisible by 3?
The 7-digit number 86A238B is divisible by 3. What is the minimum value of (A + B)?
What is the value that must be assigned to A so that the 8-digit number 541A4888 is divisible by 9?
Find the smallest digit value for A such that 58A4 is divisible by 4.
If a 7-digit number 91056A4 is completely divisible by 3, what is the least value of A?
What is the least value that must be assigned to A so that the 8-digit number 910A3076 is divisible by 6?
What is the least value that must be assigned to A so that the number 455A1280 is divisible by 30?
The 7-digit number 92A224B is divisible by 3. What is the minimum value of (A + B)?
The 7-digit number 84A614B is divisible by 3. What is the minimum value of (A + B)?
What is the least value that must be assigned to A so that the 8-digit number 456A3264 is divisible by 12?
Important Questions from Divisibility and Remainder
- Which of the following numbers divides 6,30,605?
- What smallest number should be added to 57846 so that the sum is completely divisible by 58?
What smallest number should be added to 16809 so that the sum is completely divisible by 41?
- What smallest number should be added to 91673 so that the sum is completely divisible by 88?
- When a number divided by 8379 gives the remainder 87. What will be the remainder when the same number divided by 63?
