The 7-digit number 36A836B is divisible by 3. What is the minimum value of (A + B)?
1
A number is divisible by 3 when the sum of its digits is divisible by 3.
Digit sum of 36A836B = 3 + 6 + A + 8 + 3 + 6 + B = 26 + (A + B). So (A + B) must satisfy (26 + A + B) ≡ 0 (mod 3), i.e. A + B ≡ 1 (mod 3).
The smallest non-negative value that is ≡ 1 (mod 3) is 1 (for example A = 0, B = 1).
Hence, the answer is 1.
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select the correct answer using the code given below:
