What is the least value that must be assigned to A so that the number 604A4744 is divisible by 3?
1
A number is divisible by 3 when its digit sum is divisible by 3.
Sum of the known digits of 604A4744 = 6 + 0 + 4 + 4 + 7 + 4 + 4 = 29; total digit sum = 29 + A.
29 ÷ 3 leaves remainder 2, so we need A that makes (29 + A) a multiple of 3; smallest such non-negative A is 1 (since 29 + 1 = 30 = 3 × 10).
Hence, the answer is 1.
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select the correct answer using the code given below:
