If 90 J of work is done in moving a charge of 2,000 coulombs across V volts, find V.
0.045
The question asks us to find the voltage (V) when a certain amount of work is done to move a specific amount of charge. This problem involves the relationship between work, charge, and potential difference (voltage) in an electrical circuit.
The fundamental formula connecting these quantities is:
$$ \text{Work Done (W)} = \text{Charge (Q)} \times \text{Voltage (V)} $$
This formula can be rearranged to solve for Voltage:
$$ \text{Voltage (V)} = \frac{\text{Work Done (W)}}{\text{Charge (Q)}} $$
In this specific problem, we are given the following values:
Now, we can substitute these values into the rearranged formula to find the voltage:
$$ V = \frac{W}{Q} $$
$$ V = \frac{90 \text{ J}}{2000 \text{ C}} $$
$$ V = \frac{90}{2000} \text{ Volts} $$
To simplify the fraction, we can divide both the numerator and the denominator by 10:
$$ V = \frac{9}{200} \text{ Volts} $$
Now, perform the division:
$$ V = 0.045 \text{ Volts} $$
Therefore, the voltage across which the charge is moved is 0.045 volts.
| Quantity | Symbol | Value | Unit |
|---|---|---|---|
| Work Done | W | 90 | Joules (J) |
| Charge | Q | 2000 | Coulombs (C) |
| Voltage (to find) | V | ? | Volts (V) |
Formula used: $$ V = \frac{W}{Q} $$
Calculation: $$ V = \frac{90}{2000} = 0.045 \text{ V} $$
| Term | Definition | Unit | Formula Relationship |
|---|---|---|---|
| Work | Energy transferred when a force moves an object over a distance; in electrical terms, energy transferred to move charge. | Joule (J) | $W = QV$ |
| Charge | A fundamental property of matter that causes it to experience a force when placed in an electromagnetic field. | Coulomb (C) | $Q = W/V$ |
| Voltage (Potential Difference) | The difference in electrical potential energy per unit charge between two points in a circuit. It is the energy required per unit charge to move charge between the points. | Volt (V) | $V = W/Q$ |
Work done in moving a charge is the energy transferred to move that charge against an electric field. Voltage, or potential difference, represents how much energy is needed per unit of charge to move it from one point to another. A higher voltage means more energy is available to push each unit of charge through a circuit.
The relationship $W = QV$ is a core concept in electricity. It tells us that the total work done is proportional to both the amount of charge moved and the potential difference it moved across. If you double the charge or double the voltage, you double the work done.
Units are very important here:
The formula $V = W/Q$ shows that 1 Volt is equivalent to 1 Joule per Coulomb ($1 \text{ V} = 1 \text{ J/C}$). This unit relationship is consistent with our calculation.
9800 Joules of energy was spent to raise a mass of 80 kg. The mass was raised to a height of______
The energy possessed by a body due to its change in position or shape is called:
The kinetic energy of a ball weighing 0.5 kg moving with a velocity of 4 m/s will be:
A boy weighing 50 kg runs up a staircase of 40 steps, each of 16 height cm, in 10 s. Calculate his power. (Take g = 10 m/s 2)
The capacity to do work is called:
One horse power is equals to ________.
Mechanical energy is the combination of kinetic energy and______.
A ball of 0.1 kg is dropped from rest. When it falls through a distance of 2 m, the work done by the force of gravity is (g = 9.8 m/s 2):
If 1,200 J of work is done in pushing a trolley by 20 m, what was the force (in N) employed?
A car loses 200 kJ of kinetic energy when its speed decreases from 25 m/s to 15 m/s. Find its mass in tonnes.
Which of the following is NOT correct regarding friction?
If a pump can raise 200 liters of water through a height of 300 meters in one minute, how much work can it do in one hour?
Which of the following is an example of kinetic energy?
How much kinetic energy does a 160 g cricket ball have when it is thrown at a speed of 22 m/s?
The movement of birds is an example of _______.