How much kinetic energy does a 160 g cricket ball have when it is thrown at a speed of 22 m/s?
38.72 J
Kinetic energy is the energy an object possesses due to its motion. The amount of kinetic energy depends on the object's mass and its speed.
The formula used to calculate kinetic energy (KE) is:
$$ KE = \frac{1}{2}mv^2 $$
Where:
We are given the following information:
First, we need to convert the mass from grams (g) to kilograms (kg) because the standard unit for mass in the kinetic energy formula is kilograms.
$$ 1 \text{ kg} = 1000 \text{ g} $$
So, the mass in kilograms is:
$$ m = \frac{160 \text{ g}}{1000 \text{ g/kg}} = 0.160 \text{ kg} $$
Now, we can substitute the values into the kinetic energy formula:
$$ KE = \frac{1}{2} \times m \times v^2 $$
$$ KE = \frac{1}{2} \times 0.160 \text{ kg} \times (22 \text{ m/s})^2 $$
Calculate the square of the speed:
$$ (22 \text{ m/s})^2 = 484 \text{ m}^2/\text{s}^2 $$
Now, multiply the values:
$$ KE = 0.5 \times 0.160 \text{ kg} \times 484 \text{ m}^2/\text{s}^2 $$
$$ KE = 0.080 \text{ kg} \times 484 \text{ m}^2/\text{s}^2 $$
$$ KE = 38.72 \text{ kg} \cdot \text{m}^2/\text{s}^2 $$
Since $1 \text{ Joule (J)} = 1 \text{ kg} \cdot \text{m}^2/\text{s}^2$, the kinetic energy is:
$$ KE = 38.72 \text{ J} $$
The kinetic energy of the cricket ball is 38.72 Joules. This matches option 4.
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