If 6 cos 2 θ + cos θ = 2, 0° < θ < 90°, then the value of (cosec θ + cot θ + tan θ) is:
The correct answer is 2\sqrt 3 .
Other forms include \cos 2 \theta = \cos^2 \theta - \sin^2 \theta and \cos 2 \theta = 1 - 2 \sin^2 \theta. Reciprocal Identities: The reciprocal trigonometric functions are defined as: \cosec \theta = 1/\sin \theta, \sec \theta = 1/\cos \theta, and \cot \theta = 1/\tan \theta. Range of θ: The condition 0^\circ < \theta < 90^\circ means \theta is an acute angle in the first quadrant. In this quadrant, all basic trigonometric ratios (\sin \theta, \cos \theta, \tan \theta) are positive.
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