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Question

How many of the integers between $109$ and $121$, both inclusive, are prime numbers?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
2

Identify Integers in Range

First, list all integers between 109 and 121, inclusive:

  • 109
  • 110
  • 111
  • 112
  • 113
  • 114
  • 115
  • 116
  • 117
  • 118
  • 119
  • 120
  • 121

Check Primality of Each Integer

Determine if each number is prime. A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.

  • 109: Check divisibility by primes up to $\sqrt{109} \approx 10.4$ (2, 3, 5, 7). 109 is not divisible by any of these. 109 is prime.
  • 110: Divisible by 2, 5, 10. Not prime.
  • 111: Sum of digits $1+1+1 = 3$. Divisible by 3 ($111 = 3 \times 37$). Not prime.
  • 112: Divisible by 2. Not prime.
  • 113: Check divisibility by primes up to $\sqrt{113} \approx 10.6$ (2, 3, 5, 7). 113 is not divisible by any of these. 113 is prime.
  • 114: Divisible by 2. Not prime.
  • 115: Divisible by 5. Not prime.
  • 116: Divisible by 2. Not prime.
  • 117: Sum of digits $1+1+7 = 9$. Divisible by 3 and 9 ($117 = 9 \times 13$). Not prime.
  • 118: Divisible by 2. Not prime.
  • 119: Check divisibility by primes up to $\sqrt{119} \approx 10.9$ (2, 3, 5, 7). $119 = 7 \times 17$. Not prime.
  • 120: Divisible by 2, 3, 5, 10. Not prime.
  • 121: $121 = 11 \times 11$. Not prime.

Count the Prime Numbers

The prime numbers identified in the range are 109 and 113.

There are 2 prime numbers between 109 and 121, inclusive.

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