If product of two prime numbers A and B (A < B) is 221, then what is the value of (4A – 3B)?
1
The problem states that the product of two prime numbers, A and B, is 221, and A is less than B (A < B). We need to find the value of the expression \(4A - 3B\).
A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. Examples include 2, 3, 5, 7, 11, 13, 17, 19, and so on.
Since A and B are prime numbers and their product \(A \times B = 221\), A and B must be the prime factors of 221. To find these factors, we can test for divisibility by small prime numbers.
| \(13 \times 10 = 130\) |
| \(221 - 130 = 91\) |
| \(13 \times 7 = 91\) |
| So, \(221 = 130 + 91 = 13 \times 10 + 13 \times 7 = 13 \times (10 + 7) = 13 \times 17\). |
Both 13 and 17 are prime numbers.
We found that the prime factors of 221 are 13 and 17. The problem states that A < B. Therefore, we assign the smaller prime factor to A and the larger prime factor to B.
We can verify this: A and B are prime numbers, A < B (13 < 17), and their product \(A \times B = 13 \times 17 = 221\).
Now we substitute the values of A and B into the expression \(4A - 3B\):
\(4A - 3B = 4 \times (13) - 3 \times (17)\)
First, calculate the products:
Now, perform the subtraction:
\(52 - 51 = 1\)
So, the value of the expression \(4A - 3B\) is 1.
Let's compare our result with the given options:
Our calculated value is 1, which matches Option 3.
| Concept | Description | Example |
|---|---|---|
| Prime Number | A natural number greater than 1 with exactly two distinct positive divisors: 1 and itself. | 2, 3, 5, 7, 11, 13, 17, 19, ... |
| Composite Number | A natural number greater than 1 that has more than two positive divisors. | 4 (divisors: 1, 2, 4), 6 (divisors: 1, 2, 3, 6), 9 (divisors: 1, 3, 9) |
| Prime Factorization | Expressing a composite number as a product of its prime factors. | \(12 = 2 \times 2 \times 3 = 2^2 \times 3\) \(221 = 13 \times 17\) |
| Factors/Divisors | Numbers that divide exactly into another number without leaving a remainder. | Factors of 12 are 1, 2, 3, 4, 6, 12. Factors of 221 are 1, 13, 17, 221. |
To find the prime factors of a number, especially a smaller number like 221, you can systematically test for divisibility by prime numbers starting from the smallest (2, 3, 5, 7, 11, 13, etc.). You only need to test prime divisors up to the square root of the number you are factoring. The square root of 221 is approximately 14.8. So, we only needed to check prime numbers up to 13.
In the case of 221, we found it was not divisible by 2, 3, 5, 7, or 11. When we tried 13, we found that \(221 \div 13 = 17\). Since both 13 and 17 are prime numbers, these are the prime factors of 221.
The number whose only factors are 1 and the number itself is called a/an ________ number.
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The number 323 has