How does the peak inverse voltage requirement of a full-wave bridge rectifier compare to that of a center-tapped full-wave rectifier for a given transformer secondary voltage?
The bridge rectifier requires a lower PIV rating per diode
Let Vm be the peak voltage delivered to the load in each case.
Center-tapped rectifier: when one diode conducts, the reverse-biased diode sees the full secondary voltage (both halves), so \(\text{PIV} = 2V_m\).
Bridge rectifier: two diodes conduct in series while the other two are reverse-biased in parallel across the secondary, so each sees only \(\text{PIV} = V_m\).
So for the same output, each bridge diode needs only half the PIV rating — a key advantage of the bridge circuit, besides needing no center tap. Every rectifier diode still needs some PIV rating, and the two circuits do not need the same rating.
Hence, the answer is The bridge rectifier requires a lower PIV rating per diode.
For a rectifier circuit, the form factor (Kf) is reduced while all other operating conditions remain unchanged. What is the effect on the ripple factor?
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