1. alcohols
2. aldehydes
3. ketones
4. $\alpha$-halocarboxylic acids
The Hell-Volhard Zelinsky (HVZ) reaction is a fundamental organic chemistry reaction primarily known for its ability to introduce a halogen (bromine or chlorine) at the alpha-position ($\alpha$-position) of a carboxylic acid.
The HVZ reaction typically involves treating a carboxylic acid with elemental halogen (like $Br_2$ or $Cl_2$) in the presence of a catalytic amount of phosphorus ($P$) or phosphorus tribromide ($PBr_3$).
The process generally follows these steps:
The net result is the formation of an $\alpha$-halocarboxylic acid.
Based on the mechanism and outcome, the Hell-Volhard Zelinsky reaction specifically produces $\alpha$-halocarboxylic acids.
Phenol is brominated in solvent CS₂ at low temperature. The product formed are:
What is not true regarding compound [B]?
(A) They are higher boiling liquids than aldehydes and ketones due to extensive H bonding
(B) They are soluble in Benzene
(C) They produce alkane when heated with soda lime
(D) Produces CO₂ when treated with NaHCO₃
Choose the correct answer from the options given below:
Which of the following is the correct statement for hybridization of C-atom and number of π bonds in the Carbonyl group?
What is the product formed in the following reaction sequence?

What will be the product formed when cyclohexanone undergoes Aldol condensation?