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Question

Hell-Volhard Zelinsky reaction is used for the formation of
1. alcohols
2. aldehydes
3. ketones
4. $\alpha$-halocarboxylic acids

The correct answer is
$\alpha$-halocarboxylic acids

Understanding the Hell-Volhard Zelinsky Reaction

The Hell-Volhard Zelinsky (HVZ) reaction is a fundamental organic chemistry reaction primarily known for its ability to introduce a halogen (bromine or chlorine) at the alpha-position ($\alpha$-position) of a carboxylic acid.

Reaction Mechanism and Products

The HVZ reaction typically involves treating a carboxylic acid with elemental halogen (like $Br_2$ or $Cl_2$) in the presence of a catalytic amount of phosphorus ($P$) or phosphorus tribromide ($PBr_3$).

The process generally follows these steps:

  • The carboxylic acid reacts with $P$ or $PBr_3$ to form an acyl halide. For example, using $PBr_3$: $$3 RCH_2COOH + PBr_3 \rightarrow 3 RCH_2COBr + H_3PO_3$$
  • The acyl halide then undergoes enolization. The enol form is readily halogenated at the $\alpha$-carbon because the double bond is conjugated with the carbonyl group. $$RCH_2COBr \rightleftharpoons RCH=C(OH)Br$$ $$RCH=C(OH)Br + Br_2 \rightarrow RCHBrCOBr + HBr$$
  • The resulting $\alpha$-halo acyl halide can then react with another molecule of the starting carboxylic acid to regenerate the acyl halide and form the $\alpha$-halocarboxylic acid. $$RCHBrCOBr + RCH_2COOH \rightarrow RCHBrCOOH + RCH_2COBr$$

The net result is the formation of an $\alpha$-halocarboxylic acid.

Why Other Options Are Incorrect

  • Alcohols: Alcohols are typically formed through reduction reactions or hydrolysis of esters/alkyl halides, not directly by the HVZ reaction.
  • Aldehydes: Aldehydes can sometimes be formed from carboxylic acids via reduction, but the HVZ reaction specifically targets the $\alpha$-position for halogenation, not the carbonyl carbon itself to form an aldehyde.
  • Ketones: Ketones are usually formed from the oxidation of secondary alcohols or through Friedel-Crafts acylation, neither of which is the direct outcome of the HVZ reaction.

Conclusion

Based on the mechanism and outcome, the Hell-Volhard Zelinsky reaction specifically produces $\alpha$-halocarboxylic acids.

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Important Questions from Aldehydes, Ketones and Carboxylic Acids

  1. Phenol is brominated in solvent CS₂ at low temperature. The product formed are:

  2. What is not true regarding compound [B]?

    (A) They are higher boiling liquids than aldehydes and ketones due to extensive H bonding

    (B) They are soluble in Benzene

    (C) They produce alkane when heated with soda lime

    (D) Produces CO₂ when treated with NaHCO₃

    Choose the correct answer from the options given below:

  3. Which of the following is the correct statement for hybridization of C-atom and number of π bonds in the Carbonyl group?

  4. What is the product formed in the following reaction sequence?

  5. What will be the product formed when cyclohexanone undergoes Aldol condensation?

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