A copper plate and an aluminum plate of equal thickness and area are maintained at the same temperature difference. If the thermal conductivity of copper is twice that of aluminum, what will be the ratio of heat flow through copper to that through aluminum?
The ratio will be 2:1 for copper to aluminum.
To determine the ratio of heat flow through copper to that through aluminum, we will use the formula for heat flow through a material, which is given by the equation:
Q = \frac{{k \cdot A \cdot \Delta T}}{{d}}where:
We are given that the copper plate and the aluminum plate have equal thickness (d) and area (A), and they are maintained at the same temperature difference (\Delta T). The thermal conductivity of copper is twice that of aluminum, so we have:
Thus, the heat flow for copper and aluminum can be expressed as:
For copper:
Q_{\text{copper}} = \frac{{2k_{\text{aluminum}} \cdot A \cdot \Delta T}}{{d}}For aluminum:
Q_{\text{aluminum}} = \frac{{k_{\text{aluminum}} \cdot A \cdot \Delta T}}{{d}}The ratio of the heat flow through copper to that through aluminum is then:
\frac{{Q_{\text{copper}}}}{{Q_{\text{aluminum}}}} = \frac{{\left(\frac{{2k_{\text{aluminum}} \cdot A \cdot \Delta T}}{{d}}\right)}}{{\left(\frac{{k_{\text{aluminum}} \cdot A \cdot \Delta T}}{{d}}\right)}} = \frac{2k_{\text{aluminum}}}{k_{\text{aluminum}}}This simplifies to:
= 2:1Therefore, the correct answer is that the ratio of heat flow through copper to that through aluminum is 2:1.
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