From point 'P' on the ground, a long metallic cable is laid to the top of a cliff, making an angle of 30° with the ground such that the length of the cable laid is 450√3 metres. Find the distance between point 'P' and the foot of the cliff.
675 metres
The cable, the height of the cliff and the ground distance form a right triangle. The cable is the hypotenuse, the ground distance is the side adjacent to the \(30^\circ\) angle at P.
The relation between the adjacent side and the hypotenuse is \(\cos\theta = \dfrac{\text{adjacent}}{\text{hypotenuse}}\), so \(\text{ground distance} = \text{cable} \times \cos\theta\).
With cable \(= 450\sqrt{3}\text{ m}\) and \(\cos 30^\circ = \dfrac{\sqrt{3}}{2}\): \(\text{distance} = 450\sqrt{3} \times \dfrac{\sqrt{3}}{2}\).
Since \(\sqrt{3} \times \sqrt{3} = 3\): \(\text{distance} = \dfrac{450 \times 3}{2} = \dfrac{1350}{2}\).
This evaluates to \(675\text{ metres}\).
Key concept: choose the trig ratio linking the known side to the unknown — here hypotenuse and adjacent, so cosine. Hence the distance between P and the foot of the cliff is 675 metres.
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