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Question

From point 'P' on the ground, a long metallic cable is laid to the top of a cliff, making an angle of 30° with the ground such that the length of the cable laid is 450√3 metres. Find the distance between point 'P' and the foot of the cliff.

This question was previously asked in
SSC CHSL 2025 Tier 1 Question Paper (21-Nov-2025) (Shift 1)
The correct answer is

675 metres

The cable, the height of the cliff and the ground distance form a right triangle. The cable is the hypotenuse, the ground distance is the side adjacent to the \(30^\circ\) angle at P.

The relation between the adjacent side and the hypotenuse is \(\cos\theta = \dfrac{\text{adjacent}}{\text{hypotenuse}}\), so \(\text{ground distance} = \text{cable} \times \cos\theta\).

With cable \(= 450\sqrt{3}\text{ m}\) and \(\cos 30^\circ = \dfrac{\sqrt{3}}{2}\): \(\text{distance} = 450\sqrt{3} \times \dfrac{\sqrt{3}}{2}\).

Since \(\sqrt{3} \times \sqrt{3} = 3\): \(\text{distance} = \dfrac{450 \times 3}{2} = \dfrac{1350}{2}\).

This evaluates to \(675\text{ metres}\).

Key concept: choose the trig ratio linking the known side to the unknown — here hypotenuse and adjacent, so cosine. Hence the distance between P and the foot of the cliff is 675 metres.

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