Four numbers have been given out of which three are alike in some manner, while one is different. Choose the odd one.
57
In this type of logical reasoning question, we are given a set of items (in this case, numbers) and need to find the one that does not fit the pattern or rule that applies to the others. We need to carefully examine the given numbers: 67, 47, 17, and 57, and look for a common property shared by three of them, while the remaining one lacks that property.
Let's look closely at each number:
Based on our analysis, we found that:
Three of the numbers (17, 47, 67) share the property of being prime numbers, while the fourth number (57) is a composite number. This is the pattern that makes one number different from the others in this set.
The number that does not fit the pattern of being a prime number is 57. Therefore, 57 is the odd one out among the given numbers.
| Number | Divisible by 1 and itself only? | Prime or Composite? |
| 17 | Yes | Prime |
| 47 | Yes | Prime |
| 67 | Yes | Prime |
| 57 | No (divisible by 3 and 19) | Composite |
| Concept | Definition | Example |
| Prime Number | A natural number greater than 1 that has no positive divisors other than 1 and itself. | 2, 3, 5, 7, 11, 13, 17, 19, ... |
| Composite Number | A natural number greater than 1 that is not a prime number. It has at least one positive divisor other than 1 and itself. | 4, 6, 8, 9, 10, 12, 14, 15, 16, ... |
| Odd One Out Reasoning | Identifying the item in a set that doesn't follow the rule or pattern observed in the other items. | Finding the composite number in a list of primes. |
A common way to test if a number 'n' is prime is to check for divisibility by all prime numbers up to the square root of 'n'. If 'n' is not divisible by any of these primes, then 'n' is a prime number. For example, to test 67, we look at primes up to $\sqrt{67}$. Since $8^2 = 64$ and $9^2 = 81$, $\sqrt{67}$ is between 8 and 9. We check primes 2, 3, 5, 7. None of these divide 67, confirming it's prime.
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