Four number have been given out of which three are alike in same manner, while one is different. Choose the odd one.
51
In this question, we are given four numbers and need to identify the one that is different from the other three. This type of problem often involves finding a common property or pattern shared by three of the numbers, which is not shared by the fourth number.
Let's examine each of the given numbers to see if we can find a pattern:
Based on our analysis:
The pattern observed is that three of the numbers (23, 29, and 37) are prime numbers, while the fourth number (51) is a composite number. Therefore, 51 is the number that is different from the rest.
The numbers 23, 29, and 37 belong to the category of prime numbers. The number 51 belongs to the category of composite numbers. Thus, 51 is the odd one out in the given set.
| Number | Type | Divisors |
|---|---|---|
| 23 | Prime | 1, 23 |
| 29 | Prime | 1, 29 |
| 37 | Prime | 1, 37 |
| 51 | Composite | 1, 3, 17, 51 |
| Term | Definition | Example |
|---|---|---|
| Prime Number | A natural number greater than 1 that has exactly two distinct positive divisors: 1 and itself. | 2, 3, 5, 7, 11, ... |
| Composite Number | A natural number greater than 1 that has more than two distinct positive divisors. | 4, 6, 8, 9, 10, ... |
Odd one out questions based on numbers can have various patterns. Some common patterns include:
Solving these questions requires careful observation and testing different possible patterns to find the one that fits three of the numbers and excludes the fourth.
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