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Question

For a binomial distribution with mean 4 and standard deviation \(\sqrt{3}\), what is the value of \(P(X=0)\)?

This question was previously asked in
NDA 2 2026 GAT Question Paper (13-Sep-2026)
The correct answer is

\(\left(\dfrac{3}{4}\right)^{16}\)

For a binomial distribution, mean \(np=4\) and variance \(npq=3\), so \(q=\frac{npq}{np}=\frac{3}{4}\) and \(p=\frac{1}{4}\), giving \(n=\frac{np}{p}=16\). Then \(P(X=0)={}^{n}C_{0}\,p^{0}q^{n}=q^{n}=\left(\frac{3}{4}\right)^{16}\).

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Important Questions from Binomial Distribution

  1. In a Binomial distribution, the mean is three times its variance. What is the probability of exactly 3 successes out of 5 trials?

  2. If mean and variance of a Binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1 is

  3. For Binomial distribution, n = 10 and p = 0.6, E(X 2) (second moment about origin) is:

  4. Indicate the correct answer for the combination from the following regarding the conditions for the applicability of a binominal distribution:

    (a) There are n independent trials

    (b) Each trial has only two possible outcomes

    (c) The probabilities of two outcomes do not remain constant

    (d) The trials are independent

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  5. Find out the fallacy if any in the statement:

    “The mean and the variance of a binomial distribution is 16.2 and 29.4 respectively.”

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