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Consider a random variable X which follows Binomial distribution with parameters n = 10 and \(\rm p = \dfrac{1}{5}\) . Then Y = 10 - X follows Binomial distribution with parameters n' and p' respectively given by

This question was previously asked in
NDA 2020 GAT Previous Year Paper (06-Sep-2020)
The correct answer is \(10, \dfrac{4}{5}\)

Understanding Binomial Distribution and Transformations

The question asks about the distribution of a new random variable Y, defined as Y = 10 - X, where X follows a Binomial distribution with specific parameters. To solve this, we first need to understand the properties of a Binomial distribution and how transformations affect it.

A random variable X follows a Binomial distribution with parameters n and p, denoted as \( \rm X \sim B(n, p) \), if it represents the number of successes in n independent Bernoulli trials, where the probability of success in each trial is p. The probability of failure in each trial is q = 1 - p.

In this problem, we are given that X follows a Binomial distribution with:

  • Number of trials, \( \rm n = 10 \)
  • Probability of success in each trial, \( \rm p = \dfrac{1}{5} \)

So, \( \rm X \sim B\left(10, \dfrac{1}{5}\right) \). The probability of failure in each trial is \( \rm q = 1 - p = 1 - \dfrac{1}{5} = \dfrac{4}{5} \).

Analyzing the Transformation Y = 10 - X

The new random variable is defined as \( \rm Y = 10 - X \). Since X represents the number of successes in 10 trials, Y = 10 - X must represent the number of *failures* in the same 10 trials.

Let's consider the outcomes of the 10 independent trials:

  • Each trial results in either a success (with probability \( \rm p = 1/5 \)) or a failure (with probability \( \rm q = 4/5 \)).
  • The total number of trials is fixed at 10.
  • The trials are independent.

If X counts the number of successes out of 10 trials, then Y = 10 - X counts the number of failures out of these same 10 trials. The probability of a 'failure' in the context of X is actually the 'success' probability in the context of Y.

Determining the Parameters for Y

Y represents the number of failures in 10 independent trials. The probability of a failure in a single trial is \( \rm q = 1 - p = \dfrac{4}{5} \).

Therefore, Y also follows a Binomial distribution with:

  • Number of trials, \( \rm n' = 10 \) (the total number of trials remains 10)
  • Probability of 'success' (which is failure for X) in each trial, \( \rm p' = q = \dfrac{4}{5} \)

So, \( \rm Y \sim B\left(10, \dfrac{4}{5}\right) \).

Comparing this with the general form \( \rm B(n', p') \), we find that \( \rm n' = 10 \) and \( \rm p' = \dfrac{4}{5} \).

Summary of Distribution Parameters

Random Variable Distribution Number of Trials Probability of Success
X Binomial \( \rm n = 10 \) \( \rm p = \dfrac{1}{5} \)
Y = 10 - X Binomial \( \rm n' = 10 \) \( \rm p' = \dfrac{4}{5} \)

Thus, Y follows a Binomial distribution with parameters n' = 10 and p' = \( \dfrac{4}{5} \).

Revision Table: Key Binomial Concepts

Concept Description
Binomial Distribution \( \rm B(n, p) \) Models the number of successes in \( \rm n \) independent Bernoulli trials.
Parameters \( \rm n \) and \( \rm p \) \( \rm n \): Number of trials, \( \rm p \): Probability of success per trial.
Probability of Failure \( \rm q \) \( \rm q = 1 - p \). Probability of failure per trial.
\( \rm Y = n - X \) Transformation If \( \rm X \sim B(n, p) \) is number of successes, \( \rm Y = n - X \) is the number of failures.
Distribution of \( \rm Y = n - X \) If \( \rm X \sim B(n, p) \), then \( \rm Y = n - X \sim B(n, 1-p) \).

Additional Information: Properties of Binomial Distribution

The Binomial distribution is a fundamental discrete probability distribution. Here are some additional points:

  • The probability mass function (PMF) of \( \rm X \sim B(n, p) \) is given by \( \rm P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \) for \( \rm k = 0, 1, \ldots, n \).
  • The mean of a Binomial distribution is \( \rm E(X) = np \).
  • The variance of a Binomial distribution is \( \rm Var(X) = np(1-p) \).
  • The sum of two independent Binomial random variables with the same probability of success \( \rm p \), say \( \rm X_1 \sim B(n_1, p) \) and \( \rm X_2 \sim B(n_2, p) \), follows a Binomial distribution \( \rm X_1 + X_2 \sim B(n_1 + n_2, p) \).
  • The transformation \( \rm Y = n - X \) essentially switches the roles of success and failure, hence the probability parameter changes from \( \rm p \) to \( \rm 1-p \). The number of trials remains the same because Y counts outcomes from the same set of n trials.
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  1. In a Binomial distribution, the mean is three times its variance. What is the probability of exactly 3 successes out of 5 trials?

  2. If mean and variance of a Binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1 is

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Important Questions from Binomial Distribution

  1. In a Binomial distribution, the mean is three times its variance. What is the probability of exactly 3 successes out of 5 trials?

  2. If mean and variance of a Binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1 is

  3. For Binomial distribution, n = 10 and p = 0.6, E(X 2) (second moment about origin) is:

  4. Indicate the correct answer for the combination from the following regarding the conditions for the applicability of a binominal distribution:

    (a) There are n independent trials

    (b) Each trial has only two possible outcomes

    (c) The probabilities of two outcomes do not remain constant

    (d) The trials are independent

    Which of the following options is correct?

  5. Find out the fallacy if any in the statement:

    “The mean and the variance of a binomial distribution is 16.2 and 29.4 respectively.”

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