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Consider a random variable X which follows Binomial distribution with parameters n = 10 and \(\rm p = \dfrac{1}{5}\) . Then Y = 10 - X follows Binomial distribution with parameters n' and p' respectively given by

This question was previously asked in
NDA 2020 GAT Previous Year Paper (06-Sep-2020)
The correct answer is \(10, \dfrac{4}{5}\)

Understanding Binomial Distribution and Transformations

The question asks about the distribution of a new random variable Y, defined as Y = 10 - X, where X follows a Binomial distribution with specific parameters. To solve this, we first need to understand the properties of a Binomial distribution and how transformations affect it.

A random variable X follows a Binomial distribution with parameters n and p, denoted as \( \rm X \sim B(n, p) \), if it represents the number of successes in n independent Bernoulli trials, where the probability of success in each trial is p. The probability of failure in each trial is q = 1 - p.

In this problem, we are given that X follows a Binomial distribution with:

  • Number of trials, \( \rm n = 10 \)
  • Probability of success in each trial, \( \rm p = \dfrac{1}{5} \)

So, \( \rm X \sim B\left(10, \dfrac{1}{5}\right) \). The probability of failure in each trial is \( \rm q = 1 - p = 1 - \dfrac{1}{5} = \dfrac{4}{5} \).

Analyzing the Transformation Y = 10 - X

The new random variable is defined as \( \rm Y = 10 - X \). Since X represents the number of successes in 10 trials, Y = 10 - X must represent the number of *failures* in the same 10 trials.

Let's consider the outcomes of the 10 independent trials:

  • Each trial results in either a success (with probability \( \rm p = 1/5 \)) or a failure (with probability \( \rm q = 4/5 \)).
  • The total number of trials is fixed at 10.
  • The trials are independent.

If X counts the number of successes out of 10 trials, then Y = 10 - X counts the number of failures out of these same 10 trials. The probability of a 'failure' in the context of X is actually the 'success' probability in the context of Y.

Determining the Parameters for Y

Y represents the number of failures in 10 independent trials. The probability of a failure in a single trial is \( \rm q = 1 - p = \dfrac{4}{5} \).

Therefore, Y also follows a Binomial distribution with:

  • Number of trials, \( \rm n' = 10 \) (the total number of trials remains 10)
  • Probability of 'success' (which is failure for X) in each trial, \( \rm p' = q = \dfrac{4}{5} \)

So, \( \rm Y \sim B\left(10, \dfrac{4}{5}\right) \).

Comparing this with the general form \( \rm B(n', p') \), we find that \( \rm n' = 10 \) and \( \rm p' = \dfrac{4}{5} \).

Summary of Distribution Parameters

Random Variable Distribution Number of Trials Probability of Success
X Binomial \( \rm n = 10 \) \( \rm p = \dfrac{1}{5} \)
Y = 10 - X Binomial \( \rm n' = 10 \) \( \rm p' = \dfrac{4}{5} \)

Thus, Y follows a Binomial distribution with parameters n' = 10 and p' = \( \dfrac{4}{5} \).

Revision Table: Key Binomial Concepts

Concept Description
Binomial Distribution \( \rm B(n, p) \) Models the number of successes in \( \rm n \) independent Bernoulli trials.
Parameters \( \rm n \) and \( \rm p \) \( \rm n \): Number of trials, \( \rm p \): Probability of success per trial.
Probability of Failure \( \rm q \) \( \rm q = 1 - p \). Probability of failure per trial.
\( \rm Y = n - X \) Transformation If \( \rm X \sim B(n, p) \) is number of successes, \( \rm Y = n - X \) is the number of failures.
Distribution of \( \rm Y = n - X \) If \( \rm X \sim B(n, p) \), then \( \rm Y = n - X \sim B(n, 1-p) \).

Additional Information: Properties of Binomial Distribution

The Binomial distribution is a fundamental discrete probability distribution. Here are some additional points:

  • The probability mass function (PMF) of \( \rm X \sim B(n, p) \) is given by \( \rm P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \) for \( \rm k = 0, 1, \ldots, n \).
  • The mean of a Binomial distribution is \( \rm E(X) = np \).
  • The variance of a Binomial distribution is \( \rm Var(X) = np(1-p) \).
  • The sum of two independent Binomial random variables with the same probability of success \( \rm p \), say \( \rm X_1 \sim B(n_1, p) \) and \( \rm X_2 \sim B(n_2, p) \), follows a Binomial distribution \( \rm X_1 + X_2 \sim B(n_1 + n_2, p) \).
  • The transformation \( \rm Y = n - X \) essentially switches the roles of success and failure, hence the probability parameter changes from \( \rm p \) to \( \rm 1-p \). The number of trials remains the same because Y counts outcomes from the same set of n trials.
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  1. In a Binomial distribution, the mean is three times its variance. What is the probability of exactly 3 successes out of 5 trials?

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Important Questions from Binomial Distribution

  1. In a Binomial distribution, the mean is three times its variance. What is the probability of exactly 3 successes out of 5 trials?

  2. If mean and variance of a Binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1 is

  3. For Binomial distribution, n = 10 and p = 0.6, E(X 2) (second moment about origin) is:

  4. Find out the fallacy if any in the statement:

    “The mean and the variance of a binomial distribution is 16.2 and 29.4 respectively.”

  5. If log e(x) is normally distributed with mean 1 and variance 4, then P(0.5 < x < 2) is:

    (where the area between z = 0 and z = 0.25 is 0.0987 and the area between z = 0 and z = 0.5 is 0.1915)

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