Consider a random variable X which follows Binomial distribution with parameters n = 10 and \(\rm p = \dfrac{1}{5}\) . Then Y = 10 - X follows Binomial distribution with parameters n' and p' respectively given by
The question asks about the distribution of a new random variable Y, defined as Y = 10 - X, where X follows a Binomial distribution with specific parameters. To solve this, we first need to understand the properties of a Binomial distribution and how transformations affect it.
A random variable X follows a Binomial distribution with parameters n and p, denoted as \( \rm X \sim B(n, p) \), if it represents the number of successes in n independent Bernoulli trials, where the probability of success in each trial is p. The probability of failure in each trial is q = 1 - p.
In this problem, we are given that X follows a Binomial distribution with:
So, \( \rm X \sim B\left(10, \dfrac{1}{5}\right) \). The probability of failure in each trial is \( \rm q = 1 - p = 1 - \dfrac{1}{5} = \dfrac{4}{5} \).
The new random variable is defined as \( \rm Y = 10 - X \). Since X represents the number of successes in 10 trials, Y = 10 - X must represent the number of *failures* in the same 10 trials.
Let's consider the outcomes of the 10 independent trials:
If X counts the number of successes out of 10 trials, then Y = 10 - X counts the number of failures out of these same 10 trials. The probability of a 'failure' in the context of X is actually the 'success' probability in the context of Y.
Y represents the number of failures in 10 independent trials. The probability of a failure in a single trial is \( \rm q = 1 - p = \dfrac{4}{5} \).
Therefore, Y also follows a Binomial distribution with:
So, \( \rm Y \sim B\left(10, \dfrac{4}{5}\right) \).
Comparing this with the general form \( \rm B(n', p') \), we find that \( \rm n' = 10 \) and \( \rm p' = \dfrac{4}{5} \).
| Random Variable | Distribution | Number of Trials | Probability of Success |
|---|---|---|---|
| X | Binomial | \( \rm n = 10 \) | \( \rm p = \dfrac{1}{5} \) |
| Y = 10 - X | Binomial | \( \rm n' = 10 \) | \( \rm p' = \dfrac{4}{5} \) |
Thus, Y follows a Binomial distribution with parameters n' = 10 and p' = \( \dfrac{4}{5} \).
| Concept | Description |
|---|---|
| Binomial Distribution \( \rm B(n, p) \) | Models the number of successes in \( \rm n \) independent Bernoulli trials. |
| Parameters \( \rm n \) and \( \rm p \) | \( \rm n \): Number of trials, \( \rm p \): Probability of success per trial. |
| Probability of Failure \( \rm q \) | \( \rm q = 1 - p \). Probability of failure per trial. |
| \( \rm Y = n - X \) Transformation | If \( \rm X \sim B(n, p) \) is number of successes, \( \rm Y = n - X \) is the number of failures. |
| Distribution of \( \rm Y = n - X \) | If \( \rm X \sim B(n, p) \), then \( \rm Y = n - X \sim B(n, 1-p) \). |
The Binomial distribution is a fundamental discrete probability distribution. Here are some additional points:
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Indicate the correct answer for the combination from the following regarding the conditions for the applicability of a binominal distribution:
(a) There are n independent trials
(b) Each trial has only two possible outcomes
(c) The probabilities of two outcomes do not remain constant
(d) The trials are independent
Which of the following options is correct?
Find out the fallacy if any in the statement:
“The mean and the variance of a binomial distribution is 16.2 and 29.4 respectively.”