Consider a random variable X which follows Binomial distribution with parameters n = 10 and \(\rm p = \dfrac{1}{5}\) . Then Y = 10 - X follows Binomial distribution with parameters n' and p' respectively given by
The question asks about the distribution of a new random variable Y, defined as Y = 10 - X, where X follows a Binomial distribution with specific parameters. To solve this, we first need to understand the properties of a Binomial distribution and how transformations affect it.
A random variable X follows a Binomial distribution with parameters n and p, denoted as \( \rm X \sim B(n, p) \), if it represents the number of successes in n independent Bernoulli trials, where the probability of success in each trial is p. The probability of failure in each trial is q = 1 - p.
In this problem, we are given that X follows a Binomial distribution with:
So, \( \rm X \sim B\left(10, \dfrac{1}{5}\right) \). The probability of failure in each trial is \( \rm q = 1 - p = 1 - \dfrac{1}{5} = \dfrac{4}{5} \).
The new random variable is defined as \( \rm Y = 10 - X \). Since X represents the number of successes in 10 trials, Y = 10 - X must represent the number of *failures* in the same 10 trials.
Let's consider the outcomes of the 10 independent trials:
If X counts the number of successes out of 10 trials, then Y = 10 - X counts the number of failures out of these same 10 trials. The probability of a 'failure' in the context of X is actually the 'success' probability in the context of Y.
Y represents the number of failures in 10 independent trials. The probability of a failure in a single trial is \( \rm q = 1 - p = \dfrac{4}{5} \).
Therefore, Y also follows a Binomial distribution with:
So, \( \rm Y \sim B\left(10, \dfrac{4}{5}\right) \).
Comparing this with the general form \( \rm B(n', p') \), we find that \( \rm n' = 10 \) and \( \rm p' = \dfrac{4}{5} \).
| Random Variable | Distribution | Number of Trials | Probability of Success |
|---|---|---|---|
| X | Binomial | \( \rm n = 10 \) | \( \rm p = \dfrac{1}{5} \) |
| Y = 10 - X | Binomial | \( \rm n' = 10 \) | \( \rm p' = \dfrac{4}{5} \) |
Thus, Y follows a Binomial distribution with parameters n' = 10 and p' = \( \dfrac{4}{5} \).
| Concept | Description |
|---|---|
| Binomial Distribution \( \rm B(n, p) \) | Models the number of successes in \( \rm n \) independent Bernoulli trials. |
| Parameters \( \rm n \) and \( \rm p \) | \( \rm n \): Number of trials, \( \rm p \): Probability of success per trial. |
| Probability of Failure \( \rm q \) | \( \rm q = 1 - p \). Probability of failure per trial. |
| \( \rm Y = n - X \) Transformation | If \( \rm X \sim B(n, p) \) is number of successes, \( \rm Y = n - X \) is the number of failures. |
| Distribution of \( \rm Y = n - X \) | If \( \rm X \sim B(n, p) \), then \( \rm Y = n - X \sim B(n, 1-p) \). |
The Binomial distribution is a fundamental discrete probability distribution. Here are some additional points:
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