Find the value of \(m\) which satisfies \(\left(\frac{19}{10}\right)^7 \times \left(\frac{10}{19}\right)^6 \times \left(\frac{19}{10}\right)^{10} = \left(\frac{10}{19}\right)^{6m + 18}\).
\(-\frac{29}{6}\)
Combine the powers of \(\frac{19}{10}\) on the LHS: \(\left(\frac{19}{10}\right)^7 \times \left(\frac{19}{10}\right)^{10} = \left(\frac{19}{10}\right)^{17}\).
Convert \(\left(\frac{10}{19}\right)^6\) to base \(\frac{19}{10}\): \(\left(\frac{10}{19}\right)^6 = \left(\frac{19}{10}\right)^{-6}\).
So the LHS becomes: \(\left(\frac{19}{10}\right)^{17-6} = \left(\frac{19}{10}\right)^{11}\).
Express LHS in terms of \(\frac{10}{19}\): \(\left(\frac{19}{10}\right)^{11} = \left(\frac{10}{19}\right)^{-11}\).
Equate with RHS: \(6m + 18 = -11\).
Solve: \(6m = -29 \Rightarrow m = -\frac{29}{6}\).
Hence, the value of \(m\) is \(-\frac{29}{6}\).
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